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2 years ago

G= {(-5,5), (6, 8), (-5, -5)} What is the domain and range

Mathematics

1 answer:

blagie [28]2 years ago

6 0

Answer:

I'm pretty sure domain is x and range is why which would mean that:

domain: -5,6

range: 5,8,-5

Step-by-step explanation:

Hope this helps:)...if not then sorry for wasting you time and I hope you find the right answer and may God bless you:)

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Assoli18 [71]

Answer:

AB is parallel to A'B'.

DO,1/2 (1/2x, 1/2y) =

The distance from A' to the origin is half the distance from A to the origin.

Step-by-step explanation:

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3 years ago

PLEASE HELP NOW NOW NOW PLEASE PLEASE HELP

bija089 [108]

Answer:

$46.00

Step-by-step explanation:

$46.00 - $20 + $5 = $21

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3 years ago

What is this answer

alexandr1967 [171]

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3 years ago

Suzanne is looking at taking out a personal loan. Opportunity Loans is offering her $1600 at 3.45% for 1 year, with interest com

AleksAgata [21]

Step-by-step explanation:

So the general formula for compound interest is $A = P(1+\frac{r}{n})^{nt}$ where r is the interest rate, t is the time in years, and n is the amount of compounds per year. So plugging in the values for both equations you'll get

Opportunity Loans:

$A = 1600(1+\frac{0.0345}{12})^{(12)(1)}$

$A = 1600(1.002875)^{12}$

$A \approx 1600(1.035)$

$A = \$1,656.08$

Now to find the interest accrued on this loan you simply subtract 1600 from the A or final amount

$Interest=1656.08-1600\\Interest=56.08$

General Loans:

$A = 1600(1+\frac{0.042}{4})^{(4)(1)}$

$A = 1600(1.0105)^4$

$A \approx 1600(1.042)$

$A = 1,668.27$

To find the interest we do the same thing we did in the previous problem

$interest = 1668.27-1600\\interest=68.27$

Opportunity loans has the least amount of interest after a year

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2 years ago

Please help me .. thank you

KiRa [710]

Step-by-step explanation:

Break down every term into prime factors. ...

Look for factors that appear in every single term to determine the GCF. ...

Factor the GCF out from every term in front of parentheses, and leave the remnants inside the parentheses. ...

Multiply out to simplify each term.

5 0

2 years ago

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