1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
Answer:
The correct option is B.
Step-by-step explanation:
It is given that Joe paid 14.00 for a board game this is 70% of the original price what is the original price.
Let the original price of board game be x.


Multiply both sides by 10.

Divide both sides by 7.

The original price is 20. Therefore the correct option is B.
Answer:
Same here.
Step-by-step explanation:
I'm usually bored, that's why I mainly use this site.
:D
Answer:
6.86
Step-by-step explanation:
ask if you dont understand