Answer:the horizontal displacement is 34.64 meters
The maximum height is 15 meters
Step-by-step explanation:
As the ball moves from the ground at 30 degrees, it travels through a parabolic path. It can therefore be likened to a projectile. The horizontal displacement to where it lands is the range. The formula for determining range,R is
R = U^2Sin2#)/g
Where
U represents the initial velocity of the ball
g is acceleration due to gravity
# represents the angle above the horizontal.
From the information given
# = 30 degrees
U = 20 m/s
g = 10m/s^2
R = 20^2Sin2×30)/10 = (400Sin60)/20 = (400×0.8660)/10
= 34.64 meters
To determine the maximum height of the ball, H,
H = (U^2Sin^2#)/2g
H = (20^2 × Sin^2 30)/2×10
H = (400 × 0.866^2)/20 = 15 meters
You can see that you're constantly subtracting 8 to get the next number. So, we have
So, as you can see, to get the n-th term we must subtract (n-1) times 8 from the original number.
Answer:
Positive 8
Step-by-step explanation:
Answer:
2. the interquartile range is 20
3. 80 is the median.
Step-by-step explanation:
have a nice day.
