7 squared = 49 and 9 squared= 81 add up 49 and 81 and you get 130
let's firstly convert the mixed fraction to improper fraction and then divide.
![\bf \stackrel{mixed}{2\frac{1}{2}}\implies \cfrac{2\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{5}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{5}{2}\div 4\implies \cfrac{5}{2}\div \cfrac{4}{1}\implies \cfrac{5}{2}\cdot \cfrac{1}{4}\implies \cfrac{5}{8}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B2%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B5%7D%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B5%7D%7B2%7D%5Cdiv%204%5Cimplies%20%5Ccfrac%7B5%7D%7B2%7D%5Cdiv%20%5Ccfrac%7B4%7D%7B1%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B2%7D%5Ccdot%20%5Ccfrac%7B1%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B8%7D)
Answer to the miscellaneous equation, is x=0
Miscellaneous equation are the equations which are not polynomial.
The question can be solved by:
Factorising:Splitting the terms to find the required solution
Completing the squares, etc
2ˣ -3ˣ=√(6ˣ-9ˣ)
-> (2ˣ -3ˣ)²=(3ˣ.2ˣ - 3²ˣ)
Squaring both sides,
-> 2²ˣ+3²ˣ- 2.3ˣ.2ˣ=(3ˣ.2ˣ - 3²ˣ)
-> 2²ˣ+2.3²ˣ-2.3ˣ.2ˣ-3ˣ.2ˣ=0
Factorising the terms,
-> 2ˣ(2ˣ-3ˣ) -2.3ˣ(2ˣ-3ˣ)=0
-> (2ˣ-3ˣ)(2ˣ-2.3ˣ)=0
Equating the braces to zero,
x=0 is the only solution.
Therefore, x =0 is the only solution
Learn more about miscellaneous equation: brainly.com/question/1214333
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The answer is C
Hopes this helps
Log ( base 2 ) ( 1 / 4 ) =
= log ( base 2 ) ( 2 ^(-2 ) ) =
= - 2 log ( base 2 ) 2 = ( because : log x^n = n log x )
= ( - 2 ) * 1 = ( because: log (base x) x = 1 )
= - 2
