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3 years ago

How do I solve this? It says solve each right angle and then to round answers to the nearest tenth.

Mathematics

1 answer:

mariarad [96]3 years ago

7 0

Answer:

19.2

Step-by-step explanation:

Add 12 squared to 15 squared(144+225)

Square root the answer( $\sqrt{369}$ )

Round to the nearest tenth(19.209)

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Fill in values for a, b and c so that the answer to this equation is x = 4.<br>a(bx+3)=c

den301095 [7]

Answer:

A=1, B=3, C=15

Step-by-step explanation:

I think that

1(3x+3)=15

3x+3=15

3x=12

x=4

7 0

3 years ago

The triangles are similar. <br> What is the value of x?<br><br> x =

saveliy_v [14]

Answer:

x = 23

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

$\frac{39}{x-10}$ = $\frac{36}{12}$ = $\frac{15}{5}$ = 3

multiply both sides by (x - 10)

3(x - 10) = 39 ( divide both sides by 3 )

x - 10 = 13 ( add 10 to both sides )

x = 23

8 0

3 years ago

Read 2 more answers

David weighs 20 pounds more than katie while jonathan weighs 120 pounds less than three times katie's weight if david and jonoth

ladessa [460]

D = k + 20
j = 3k - 120
d = j

k + 20 = 3k - 120
20 + 120 = 3k - k
140 = 2k
140/2 = k
70 = k.....so Katie weighs 70 lbs

David and Johnathan each weigh 90 lbs

3 0

3 years ago

How do you find a vector that is orthogonal to 5i + 12j ?

Rashid [163]

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\$

$\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
slope=\cfrac{12}{{{ 5}}}\qquad negative\implies -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}
\\\\\\
\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}$

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

$\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}
\\\\\\
\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}
\\\\\\
\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}$

4 0

3 years ago

Which irrational number can be multiplied by - 141 to get a product that equals 1?

stiks02 [169]

Answer:

Step-by-step explanation:

6 0

3 years ago