Answer:
The probability of selecting a family with exactly one male child is 1/4 or 0.25.
Step-by-step explanation:
Given in the question,
possible outcomes for the children's genders
{FFFF, FFFM, FFMF, FMFF, MFFF, MFFM, MFMF, MMFF, FFMM, FMFM, FMMF, FMMM, MFMM, MMFM, MMMF, MMMM}
= 16
To find,
the probability of selecting a family with exactly one male child
<h3>Probability = favourable outcomes / possible outcomes</h3>
favourable outcomes = {FFFM, FFMF, FMFF, MFFF}
= 4
Probability = 4 / 16
= 1 / 4
= 0.25
Mean: Add up the numbers and divide the sum by the number of values in the set.
6 + 9 + 2 + 4 + 3 + 6 + 5 = 35
35 / 7 = 5
Median: Sort the set from the smallest value to the largest value and select the number in the middle. If the count of the set if even, then select the two middle values and take their mean average.
2, 3, 4, 5, 6, 6, 9
^
So, the median average is 5.
Mode: What number appears the most frequently?
The mode of the set is 6 because it appears twice.
Range: Sort the set by ascending order and take the smallest value and subtract that from the largest value in the set.
9 - 2 = 7
The range is 7.
x=-3 y=0 probably wrong but it’s the root of at least one of these
