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Eva8 [605]
2 years ago
14

Provide the missing reasons for the proof. Given: AB = CB EB DB Prove: ABC ~ EBD

Mathematics
1 answer:
Umnica [9.8K]2 years ago
3 0

Answer:

Number 1 is Given.

Number 2 is the corresponding parts theorem

AB and CB are similar

also EB and DB

Number 3 is SSA similarly theorem

Step-by-step explanation:

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How do you factor this? x^{2} + 5 x- 9 = ?
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6 0
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What are the center and radius f the circle with equation xthe power of 2 +y power of 2 -4x -6y +8=0
Dovator [93]
<span>x² +y² -4x -6y +8=0
(x² -4x) +(y² -6y) = -8
We are going to complete square for x and y,
it should look like a²+2ab+b² = (a +b)², or </span>a²-2ab+b² = (a -b)²,
<span>
(x²-2*2x+2²) -2² + (y²-2*3y +3²)-3²=- 8
(x-2)²+(y-3)²-4-9=-8
</span>(x-2)²+(y-3)²=-8+13
(x-2)²+(y-3)²=5
<span>
Formula a circle (x-h)²+(y-k)²=R², where vertex has coordinates (h, k) 

So , for our circle  vertex (2,3) and radius = </span>√5<span>


</span>
6 0
3 years ago
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