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4 years ago

How long will it take for 15% contribution on $45,000 to double?

Mathematics

1 answer:

BaLLatris [955]4 years ago

5 0

Answer:

4.96 years

Step-by-step explanation:

use the rule of 72

Y = 72 / r and r = 72 / Y

y= years

r= rate

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How fast is the minivan traveling in miles per minute

s2008m [1.1K]

The van is traveling about 55.9 miles per hour.

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3 years ago

Find the greatest common factor

Vikentia [17]

Answer:

3x^2y^2

Step-by-step explanation:

I think:

3*2*x*x*x*y*y*y*y

3*3*x*x*y*y

3*6*x*x*x*y*y

They all have 3x^2y^2 in common.

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3 years ago

3x+3y=180 what is the answer to this problem

Hatshy [7]

Answer:

If you are solving the equation for x :

3x + 3y = 180

3x = -3y + 180

x = -y + 60 or x = 60 - y

If you are solving the equation for y:

3x + 3y = 180

3y = -3x + 180

y = -x + 60 or y = 60 - x

3 0

3 years ago

Karissa deposits $165 into a new savings account. The account earns 2.75% simple interest per year. Karissa plans on keeping the

enyata [817]

Answer:$382

Step-by-step explanation:

To get The interest for 4 years

Amount*rate*time*duration

165*0.0275*12*4=$217

165+217=$382

3 0

3 years ago

Please help

Alekssandra [29.7K]

Answer:

25 in x 15 in

Step-by-step explanation:

Given:

Length = 3/5 the width
Area = 375 in²

Let width = $x$

Therefore, length = 3/5 $x$

First create an equation for the area of the picture based on the given information for its width and length:

$\begin{aligned} \implies \textsf{Area of original picture} & = \sf width \times length\\& = x\left(\dfrac{3}{5}x\right)\\& = \dfrac{3}{5}x^2\end{aligned}$

We are told the area of the enlarged picture is 375 in². Therefore, substitute this into the equation and solve for $x$ to find the width of the enlarged picture:

$\begin{aligned}\textsf{Area} & = 375\\ \implies \dfrac{3}{5}x^2 & = 375\\ x^2 & =375 \cdot \dfrac{5}{3}\\ x^2 & =625\\ x & = \sqrt{625}\\ x& = 25\end{aligned}$

Therefore, the width of the enlarged picture is 25 in.

Substitute the found value of $x$ into the expression for length to find the length of the enlarged picture:

$\begin{aligned}\sf Length & = \dfrac{3}{5}x\\\\\implies \sf Length & = \dfrac{3}{5}(25)\\\\& = 15\: \sf in\end{aligned}$

Therefore, the dimensions of the enlarged picture are <u>25 in x 15 in</u>. The width is 25 in and the length is 15 in, as the length is 3/5 of the width.

5 0

2 years ago