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3 years ago

The cost of carpeting a square yard is $8.60. How much does it cost to carpet 9.7 square yards?

Mathematics

1 answer:

Fittoniya [83]3 years ago

4 0

The answer would be 83.42 just multiple them and ur all set. :)

Pls mark me as brainiest

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Ms. jones wants to take her students for all of her classes on a field trip to see a Broadway production. There are three shows

lina2011 [118]

Answer:

Step-by-step explanation:

Because it is a random sample

5 0

3 years ago

3y''-6y'+6y=e*x sexcx

Simora [160]

From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

$3r^2-6r+6=0\iff r^2-2r+2=0$

which has roots at $r=1\pm i$ . This admits the two fundamental solutions

$y_1=e^x\cos x$
$y_2=e^x\sin x$

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

$y_p=u_1y_1+u_2y_2$

where

$u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$
$u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$

and $W(y_1,y_2)$ is the Wronskian of the fundamental solutions. We have

$W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}$

and so

$u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx$
$u_1=\dfrac13\ln|\cos x|$

$u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx$
$u_2=\dfrac13x$

Therefore the particular solution is

$y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

so that the general solution to the ODE is

$y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

7 0

3 years ago

Factor completely <br> 4x^2 + 24x - 64

lara31 [8.8K]

First see you can factor out 4. What is left is x^2 + 6x - 16.
That can be factored as (x+8)(x-2) so the total factorization is

4(x+8)(x-2)

7 0

3 years ago

If f(1) = 10 and f(n) = f(n = 1) – 4 then find the value of f(5).

svetoff [14.1K]

Given:

$f(1)=10$ and $f(n)=f(n-1)-4$ .

To find:

The value of f(5).

Solution:

We have,

$f(n)=f(n-1)-4$

For $n=2$ ,

$f(2)=f(2-1)-4$

$f(2)=f(1)-4$

$f(2)=10-4$

$f(2)=6$

For $n=3$ ,

$f(3)=f(3-1)-4$

$f(3)=f(2)-4$

$f(3)=6-4$

$f(3)=2$

For $n=4$ ,

$f(4)=f(4-1)-4$

$f(4)=f(3)-4$

$f(4)=2-4$

$f(4)=-2$

For $n=5$ ,

$f(5)=f(5-1)-4$

$f(5)=f(4)-4$

$f(5)=-2-4$

$f(5)=-6$

Therefore, the value of $f(5)$ is $-6$ .

5 0

3 years ago

Please help me with a explanation

blagie [28]

Answer:

x = -3 or x = 3

Step-by-step explanation:

Subtract 9 from both sides.

x^2 - 9 = 0

Factor the left side. There is no common factor of the terms. It is a binomial which is the difference of two squares, so it factors into the product of a sum and a difference.

(x + 3)(x - 3) = 0

Set each factor equal to zero.

x + 3 = 0 or x - 3 = 0

Solve each equation.

x = -3 or x = 3

3 0

3 years ago