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zhannawk [14.2K]
3 years ago
9

Please help me... I think its the third graph or the last . correct me if im wrong

Mathematics
2 answers:
miss Akunina [59]3 years ago
4 0
Hi there!

I believe the answer you are looking for - is the third graph.

Hope this helps!

~Alexa
Romashka-Z-Leto [24]3 years ago
4 0
The third graph y is the answer i hope this helps you <span />
You might be interested in
What is 4855/200 simplified
EleoNora [17]

Answer:

The answer is 2427.5

Step-by-step explanation:

The fraction consists of two numbers and a fraction bar: 4,855/200

The number above the bar is called numerator: 4,855

The number below the bar is called denominator: 200

The fraction bar means that the two numbers are dividing themselves.

To get fraction's value divide the numerator by the denominator:

Value = 4,855 ÷ 200

To calculate the greatest common factor, GCF:

1. Build the prime factorizations of the numerator and denominator.

2. Multiply all the common prime factors, by the lowest exponents.

Factor both the numerator and denominator, break them down to prime factors:

Prime Factorization of a number: finding the prime numbers that multiply together to make that number.

4,855 = 5 × 971;

4,855 is a composite number;

In exponential notation:

200 = 2 × 2 × 2 × 5 × 5 = 23 × 52;

200 is a composite number;

3 0
3 years ago
HELPPPP!!!
Hatshy [7]

Answer:

(x - 1)²/4² - (y - 2)²/2² = 1 ⇒ The bold labels are the choices

Step-by-step explanation:

* Lets explain how to solve this problem

- The equation of the hyperbola is x² - 4y² - 2x + 16y - 31 = 0

- The standard form of the equation of hyperbola is

  (x - h)²/a² - (y - k)²/b² = 1 where a > b

- So lets collect x in a bracket and make it a completing square and

  also collect y in a bracket and make it a completing square

∵ x² - 4y² - 2x + 16y - 31 = 0

∴ (x² - 2x) + (-4y² + 16y) - 31 = 0

- Take from the second bracket -4 as a common factor

∴ (x² - 2x) + -4(y² - 4y) - 31 = 0

∴ (x² - 2x) - 4(y² - 4y) - 31 = 0

- Lets make (x² - 2x) completing square

∵ √x² = x

∴ The 1st term in the bracket is x

∵ 2x ÷ 2 = x

∴ The product of the 1st term and the 2nd term is x

∵ The 1st term is x

∴ the second term = x ÷ x = 1

∴ The bracket is (x - 1)²

∵  (x - 1)² = (x² - 2x + 1)

∴ To complete the square add 1 to the bracket and subtract 1 out

   the bracket to keep the equation as it

∴ (x² - 2x + 1) - 1

- We will do the same withe bracket of y

- Lets make 4(y² - 4y) completing square

∵ √y² = y

∴ The 1st term in the bracket is x

∵ 4y ÷ 2 = 2y

∴ The product of the 1st term and the 2nd term is 2y

∵ The 1st term is y

∴ the second term = 2y ÷ y = 2

∴ The bracket is 4(y - 2)²

∵ 4(y - 2)² = 4(y² - 4y + 4)

∴ To complete the square add 4 to the bracket and subtract 4 out

   the bracket to keep the equation as it

∴ 4[y² - 4y + 4) - 4]

- Lets put the equation after making the completing square

∴ (x - 1)² - 1 - 4[(y - 2)² - 4] - 31 = 0 ⇒ simplify

∴ (x - 1)² - 1 - 4(y - 2)² + 16 - 31 = 0 ⇒ add the numerical terms

∴ (x - 1)² - 4(y - 2)² - 16 = 0 ⇒ add 14 to both sides

∴ (x - 1)² - 4(y - 2)² = 16 ⇒ divide both sides by 16

∴ (x - 1)²/16 - (y - 2)²/4 = 1

∵ 16 = (4)² and 4 = (2)²

∴ The standard form of the equation of the hyperbola is

   (x - 1)²/4² - (y - 2)²/2² = 1

4 0
4 years ago
The line tangent to the graph of g(x) = x^{3}-4x+1 at the point (2, 1) is given by the formula
Usimov [2.4K]

well, about A and D, I just plugged the values on the slope formula of

\bf \begin{array}{llll} g(x)=x^3-4x+1\\ L(x) = 8(x-2)+1 \end{array} \qquad \begin{cases} x_1=1.9\\ x_2=2.1 \end{cases}\implies \cfrac{f(b)-f(a)}{b-a}

for A the values are 8.01 and 8.0, so indeed those "slopes" are close. \textit{\huge \checkmark}

for D the values are -2.25 and 8.0, so no dice on that one.

for B, let's check the y-intercept for g(x), by setting x = 0, we end up g(0) = 0³-4(0)+1, which gives us g(0) = 1.

checking L(x) y-intercept, well, L(x) is in slope-intercept form, thus the +1 sticking out on the far right is the y-intercept, so, dice. \textit{\huge \checkmark}

for C, well, the slope if L(x) is 8, since it's in slope-intercept form, the derivative of g(x) is g'(x) = 3x² - 4, and thus g'(0) = -4, so no dice.

for E, do they intercept at (2,1)?  well, come on now, L(x) is a tangent line to g(x), so that's a must for a tangent. \textit{\huge \checkmark}

for F, we know the slope of the line L(x) is 8, is g'(2) = 8?  let's check

recall that g'(x) = 3x² - 4, so g'(2) = 3(2)² - 4, meaning g'(2) = 8, so, dice. \textit{\huge \checkmark}

6 0
4 years ago
Pick the set of numbers which contain ALL perfect squares:
Bumek [7]
The answer is D I believe.
8 0
3 years ago
Read 2 more answers
Martha bought new fish for her home aquarium. She Bought 3 guppies and 2 platies for a total of 13.95.Find the price of a guppy
Crazy boy [7]
Bought the same number of Guppies and only Hank bought 2 additional Platies. Thus, let’s subtract the total of Hank and Martha
=> 18.33 – 13. 95 = 4.38
Thus, Hank paid an additional of 4.34 for 2 platies. Let’s divide to get the price of platies
=> 4.34 / 2 = = 2.19 (price of platies each.)
Let’s solve for price of guppies
=> 13.95 – 4.34 = 9.61
=> 9.61 / 3 = 3.20 (Price of guppies each.)
8 0
3 years ago
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