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2 years ago

The sum of two numbers is 56. Their product is 108. Find the larger number?

Mathematics

2 answers:

lakkis [162]2 years ago

4 0

Answer:

Step-by-step explanation:

The two numbers are 54 and 2

Their sum = 54 + 2 = 56

Their product = 54 x 2 = 108

Ahat [919]2 years ago

4 0

Answer: the larger number is 54

Step-by-step explanation:

x + y = 56

xy = 108

x = 56 - y

substitute the x value in equation

(56 -y) y = 108

56y - y^2 = 108

y^2 - 56y + 108 = 0

=(y - 2)(y - 54)

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suter [353]

Answer:

$\theta = 30^\circ, 330^\circ$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

Step-by-step explanation:

Given [Missing from the question]

Equation:

$cos\theta = \frac{\sqrt 3}{2}$

Interval:

$0 \le \theta \le 360$

$0 \le \theta \le 2\pi$

Required

Determine the values of $\theta$

The given expression:

$cos\theta = \frac{\sqrt 3}{2}$

... shows that the value of $\theta$ is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

$cos\theta = \frac{\sqrt 3}{2}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{\sqrt 3}{2})$

$\theta = 30$ --- In the first quadrant

In the fourth quadrant, the value is:

$\theta = 360 -30$

$\theta = 330$

So, the values of $\theta$ in degrees are:

$\theta = 30^\circ, 330^\circ$

Convert to radians (Multiply both angles by $\pi/180$ )

So, we have:

$\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}$

$\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}$

$\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

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Pleasee helpp mee asap

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$(4a {b}^{5} )^{4} = ({4})^{4} ( {a})^{4} ({b}^{5} )^{4} = 256 {a}^{4} {b}^{20}$

__o__o__

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