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3 years ago

Can someone please help me with this question?

Mathematics

2 answers:

natima [27]3 years ago

8 0

The answer is 0 percent

iris [78.8K]3 years ago

4 0

It would be 0% because he drove the same number of miles.

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Pass a brotha some help :(

nikitadnepr [17]

Answer and Step-by-step explanation:

Distribute the 1p to the y and -6 and distribute the 2 to the 3y and 6.

10y - 50 + 6y + 12

Now, combine like terms.

16y - 38

#teamtrees #PAW (Plant and Water)

7 0

3 years ago

A greengrocer sells a melon at a profit of 37.5% on the price he pays for it. what is the ratio the cost price to the selling pr

strojnjashka [21]

$\frac{100}{137.5} = \frac{1}{1.375}$ I simply divided by 100 and moved the decimal two places to the left.

4 0

3 years ago

I honestly don't know how I got these answers and I have a test over it coming soon. Please explain how to find the measure of t

Tju [1.3M]

Okay so a couple of things to know to best solve this problem
1) all angles in a triangle add to 180
2) a straight line the angles above it equal 180 and the angles below it add to 180
3) vertical angles are equal (vertical angles are angles that make an X the opposite angles are called vertical angles)

5 0

4 years ago

Read 2 more answers

What is the greatest number you can multiply by 4 and not go over 12?

taurus [48]

Answer:

Step-by-step explanation:

3 x 4 = 12

7 0

2 years ago

Solve for x and y it says i need 20 characters so i’m writing more

fgiga [73]

Answer:

 For y :

From pythogras theorem:

${ \tt{ {(hypotenuse)}^{2} = {(adjacent)}^{2} + {(opposite)}^{2} }} \\ { \tt{ {(7 + 3)}^{2} = \{( {x}^{2} + 9) \} {}^{2} + {y}^{2} }} \\ { \tt{100 = ( {x}^{4} + 18 {x}^{2} + 81) + {y}^{2} }} \\ { \tt{ {y}^{2} = 100 - {x}^{4} - {18x}^{2} - 81 - - - - (a) }}$

For the second largest inner triangle;

${ \tt{ {y}^{2} = {7}^{2} + {x}^{2} }} \\ { \tt{ {y}^{2} - = 49 + {x}^{2} - - - - (b) }}$

Equate (a) and (b):

${ \tt{100 - {x}^{4} - 18 {x}^{2} - 81 = 49 + {x}^{2} }} \\ { \tt{100 - 49 - 81 = {x}^{4} + 19 {x}^{2} }} \\ { \tt{ - 30 = {x}^{2}( {x}^{2} + 19x)}} \\ { \boxed{ \tt{for \: \: {x}^{2} = - 30...imaginary \: value }}} \\ {\boxed{ \tt{for \: \: ( {x}^{2} + 19x ) \: = - 30}}} \\ { \tt{ {x}^{2} + 19x + 30 = 0 }} \\ { \tt{}}$

solve the equation to get values of x, which will give you y

7 0

1 year ago