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Ket [755]
3 years ago
8

What is 3b to the second power minutes b, of b=5?

Mathematics
1 answer:
Sav [38]3 years ago
3 0
(3b)^{2} - b
where
b = 5
is 220.
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Suppose you are paid an annual salary, plus a bonus of 20% on annual sales over $500,000. Consider the two functions f(x) = x −
melisa1 [442]

Answer:

C. g\,\circ \, f (x) =g(f(x))

Step-by-step explanation:

Let be f(x) = x-500000 the excedent on annual sales and g(x) = 0.2\cdot x the bonus factor, to determine the bonus amount a composition of f(x) is g(x) must be done. That is:

g\,\circ \, f (x) =g(f(x))

Hence, the right answer is C.

7 0
3 years ago
The hexagon GIKMPR is regular. The dashed line segments form 30 degree angles.
Gwar [14]

Answer:

The correct option is (D).

Step-by-step explanation:

It is given that GIKMPR is regular hexagon. It means it has 6 vertices.

Since the central angle is 360 degree. Therefore the central angle between two consecutive vertices is

\frac{360^{\circ} }{6}=60^{\circ}

It is given that the dashed line segments form 30 degree angles.

We have rotated the hexagon about O to map PQ to RF. Since P and R are consecutive vertices, therefore the angle between them is 60 degree.

The vertex R is immediate next to the vertex P in clockwise direction.

So if we rotate the hexagon at 60 degree clockwise about O, then we can maps PQ to RF.

360^{\circ}-60^{\circ}=300^{\circ}

Therefore we can also rotate the hexagon at 300 degree counterclockwise about O, then we can maps PQ to RF.

Therefore option D is correct.


8 0
3 years ago
URGENT PLS PLS HELP WILL GIVE BRAINLIEST!!
SSSSS [86.1K]

Answer:

the second graph is likely the continuous one because the first graph stops on the x-axis

6 0
3 years ago
Which of the following expressions are polynomials
harkovskaia [24]
Its A. B. and C.............
3 0
3 years ago
Please help if u see this
jek_recluse [69]
<h3>Answer: Choice D</h3>

(f \circ g)(x) = x+12

Domain = [-3, infinity)

==================================================

Work Shown:

f(x) = x^2 + 9\\\\f(g(x)) = (g(x))^2 + 9\\\\f(g(x)) = (\sqrt{x+3})^2 + 9\\\\f(g(x)) = x+3 + 9\\\\f(g(x)) = x+12\\\\(f \circ g)(x) = x+12\\\\

In step 2, we replaced every x with g(x)

In step 3, we plugged in g(x) = sqrt(x+3)

The domain of g(x) is [-3, infinity), so this is the domain of (f \circ g)(x) as well since the composite function depends entirely on g(x). Put another way: the input of f(x) depends on the output of g(x), so that's why the domains match up.

7 0
2 years ago
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