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yanalaym [24]
3 years ago
14

The 2 pentagons above are similar. What is the area of the smaller pentagon?

Mathematics
2 answers:
AURORKA [14]3 years ago
7 0
Let As = smaller pentagon area

(7.5/2.5)^2 = 54/As

As = 6 sq.inches

The answer is 6 in^2
Anna71 [15]3 years ago
6 0
The correct answer is the third option, which is:

 6 inches²

 The explanation is shown below:

 1. You are working with the areas of the pentagons shown in the figure above. Therefore, the ratios are:

 side1²/side2²=A1/A2

 (7.5)²/(2.5)²=54/A2

 Where A2 is the the area of the smaller pentagon.

 2. Therefore, you have that the result is:

 A2=6 inches² (As you can see, it is the third option mentioned above). 
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Work out the value of z, given that x+y=42 and x/13=y/8=z/9.
Andru [333]

Answer:

z = 18

x = 26 and y = 16

Step-by-step explanation:

Given:

x + y = 42

\dfrac{x}{13}=\dfrac{y}{8}=\dfrac{z}{9}

Rewrite  x + y = 42  to make y the subject:

\implies y=42-x

Substitute this into \dfrac{x}{13}=\dfrac{y}{8}:

\implies \dfrac{x}{13}=\dfrac{42-x}{8}

Cross multiply:

\implies 8x=13(42-x)

\implies 8x=546-13x

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Substitute found value of x into x + y = 42 and solve for y:

\implies 26 + y = 42

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4 0
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