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3 years ago

9

What the answer plz help fast? If you get it right i will mark you brainless ❤️

2 answers:

Contact [7]3 years ago

4 0

Answer:

c

Step-by-step explanation:

romanna [79]3 years ago

3 0

Answer:

You'll mark me brainless?! I shouldn't answer corectly then XD

The answer (keep in mind that i'm answering incorrectly) A, or B, or D, or E.

Do you see what I did there ;)

Step-by-step explanation:

May I have brainliest please :)

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3. Which description matches the graph of the inequality?

Luda [366]

Answer: D is correct dotted and shaded below

Step-by-step explanation:

It’s a dotted line because the symbol is < or >

Everything below the line will be shaded because it’s y<, if it were y> then everything would be shaded above

6 0

3 years ago

Read 2 more answers

For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant

nirvana33 [79]

Answer:

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of $y$ with respect to $x$ over the interval by definition of secant line:

$r = \frac{y(b) -y(a)}{b-a}$ (1)

Where:

$a$ , $b$ - Lower and upper bounds of the interval.

$y(a)$ , $y(b)$ - Function exaluated at lower and upper bounds of the interval.

If we know that $y = 3\cdot x^{2}$ , $a = 3$ and $b = 6$ , then the average rate of change of $y$ with respect to $x$ over the interval is:

$r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}$

$r = 27$

The average rate of change of $y$ with respect to $x$ over the interval $[3,6]$ is 27.

b) The instantaneous rate of change can be determined by the following definition:

$y' = \lim_{h \to 0}\frac{y(x+h)-y(x)}{h}$ (2)

Where:

$h$ - Change rate.

$y(x)$ , $y(x+h)$ - Function evaluated at $x$ and $x+h$ .

If we know that $x = 3$ and $y = 3\cdot x^{2}$ , then the instantaneous rate of change of $y$ with respect to $x$ is:

$y' = \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}$

$y' = 6\cdot \lim_{h \to 0} x +3\cdot \lim_{h \to 0} h$

$y' = 6\cdot x$

$y' = 6\cdot (3)$

$y' = 18$

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

5 0

3 years ago

Simplify the algebraic expression by combining like (or similar) terms. 2x+3y2−3−y2+x−3 2 x + 3 y 2 − 3 − y 2 + x − 3

Vanyuwa [196]

The answer is -2 x + 2 y^2 + 4 y - 9.

Hope this helps! :D

6 0

4 years ago

I really need your help

nata0808 [166]

Answer: The median is 30.

1.) Line up each number in numerical order based on the data set.

- 27, 28, 28, 29, 29, 29, 30, 30, 30, 31, 31, 31, 33, 34.

2.) Cross out the numbers from inside out. (Find the middle number.)

- Because the data set has an even amount of numbers, you are left with 2 middle numbers. (30 & 30)

- In this case, you add the numbers together (30 + 30) and divide them by 2. (60/2)

- You end with the result of 30, therefore your answer (the median) is 30.

4 0

3 years ago

What multiplies to 24 and adds to negative 11?

olga_2 [115]

-8•-3 I think this is right

3 0

3 years ago