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3 years ago

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Rad 18x^5y + Rad 32xy^3 - Rad 128xy

1 answer:

True [87]3 years ago

5 0

Sqrt(18x^5y) + sqrt(32xy^3) - sqrt(128xy)
You may separate the roots to produce solvable square roots!

sqrt(9x^4)*sqrt(2xy) + sqrt(16y^2)*sqrt(2xy) - sqrt(64)*sqrt(2xy)

Simplifying makes it ...
(3x^2 + 4y - 8)*sqrt(2xy)
This should be the closest you can get to a simplified equation.

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Simplify<br> 8V 28<br><img src="https://tex.z-dn.net/?f=8%20%5Csqrt%7B28%7D%20" id="TexFormula1" title="8 \sqrt{28} " alt="8 \sq

omeli [17]

“42.3” I wish I got easy questions like you do

5 0

3 years ago

What is the solution set to this equation? Log2(x - 2) + log2x = 3

galina1969 [7]

The solution set is answer A.

7 0

3 years ago

Read 2 more answers

Solve -9 2/7 - (-10 3/7).<br> A. - 1 1/7<br><br> B. 1 1/7<br><br> C. 19 1/7<br><br> D. 19 5/7

jenyasd209 [6]

Answer:

1 5/7

Step-by-step explanation:

-9 2/7 -(-10 3/7) recall -×- = +

-9 2/7 +10 3/7

1 2+3/7

1 5/7

6 0

3 years ago

Insert parenthesis to make the<br> following true.<br> 8 + 9x3 - 1 = 50

Serjik [45]

Answer:

(8+9) 3 - 1 = 50

Step-by-step explanation:

8 + 9 = 17

17 x 3 = 51

51 - 1 = 50

8 0

2 years ago

Read 2 more answers

Please help! It’s Saturday and I only have this question left on my digital worksheet!

Natalija [7]

Answer:

<h2>The answer is option C</h2>

Step-by-step explanation:

<h3> $\frac{ {6}^{ - 3} }{ {6}^{5} }$ </h3>

Using the rules of indices

Since the bases are the same and are dividing we subtract the exponents

That's

<h3> $\frac{ {a}^{x} }{ {a}^{y} } = {a}^{x - y}$ </h3>

So we have

<h3> $\frac{ {6}^{ - 3} }{ {6}^{5} } = {6}^{ - 3 - 5} = {6}^{ - 8}$ </h3>

Using the rules of indices

<h3> ${x}^{ - y} = \frac{1}{ {x}^{y} }$ </h3>

So we have the final answer as

<h2> $\frac{1}{ {6}^{8} }$ </h2>

Hope this helps you

4 0

3 years ago