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deff fn [24]
3 years ago
5

I need help pleaseee

Mathematics
1 answer:
Nataly_w [17]3 years ago
5 0
Is this for area and perimeter? If so, first make the fraction a decimal, (that would be 3.5). Then, for permeter, add 3.5 + 3.5 + 9 + 9, which is 25, for area, multiply 3.5 by 9, which is 31.5. Hope this helped!
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Find the modulus of the complex number 6-2i
Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

Step-by-step explanation:

Given the number

6-2i

We know that

z = x + iy

where x and y are real and \sqrt{-1}=i

The modulus or absolute value of z is:

|z|\:=\sqrt{x^2+y^2}

Therefore, the modulus of 6-2i  will be:

z=6-2i

z=6+(-2)i

|z|\:=\sqrt{x^2+y^2}

|z|\:=\sqrt{6^2+\left(-2\right)^2}

    =\sqrt{6^2+2^2}

    =\sqrt{36+4}

    =\sqrt{40}

    =\sqrt{2^2}\sqrt{2\cdot \:5}

    =2\sqrt{2\cdot \:5}

   =2\sqrt{10}

Therefore, the modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

3 0
3 years ago
*5) x—&gt; 1 — x<br><br> Help please will really appreciate it
Paha777 [63]
Hey I’m sorry but I do not know the answer.
3 0
3 years ago
Plot the points (0,1), (-1,3), (2, -3) and describe the resulting graph.
ivanzaharov [21]

check the picture below.

6 0
3 years ago
How many points need to be removed from this graph
Gennadij [26K]

Answer:

3 points

Step-by-step explanation:

If you do the vertical line test, there are 3 points that need to be removed, as there can only be 1 x value for every y value in order for it to be a function.

4 0
3 years ago
Read 2 more answers
Y-125 = O A. -15 O B. -25 O c. -5 C. O D. 5 or -5​
timurjin [86]

Answer:

-5

Step-by-step explanation:

Cube root of -125 has to be -5

3 0
2 years ago
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