Answer:
Phenotypic ratio= 1:1
Genotypic ratio = 1:1
Explanation:
This is a monohybrid cross involving a single gene that specifies a color phenotype.
According to the question, WW, which is homozygous dominant i.e same allele is white while ww, which is homozygous recessive is black.
Hence a genotype Ww will possess a white phenotype since the W allele will mask the expression of w.
In a cross between a female and male with a a Genotype Ww and ww respectively. The parents alleles will be separated into gametes according to Mendel's law of segregation. (See attached image).
Ww will produce gametes W and w
ww will produce gametes w and w
The four possible offsprings will have Ww (2) and ww (2) genotypes. Hence two of them will be white while two will be black.
Hence, the phenotypic ratio will be 1:1 while the genotypic ratio will also be 1 Ww: 1 ww
Answer:
female gametophytes
Explanation:
The cell called megasporocyte (2n) is usually the mother cell of the megaspores, which are the female spores of spermatophyte plants.
After an meiosis, the megaspore mother cell (2n) will give rise to 4 megaspores (n). Three of these megaspores usually degenerate. The functional megaspore will then develop into the megagametophyte, which will be called the embryonic sac. Initially the megaspore grows and its nucleus divides.
Answer:
The correct answer is - 25%
Explanation:
A cross between true tall pea plant and heterozygous tall pea plant is the cross of tall allele whic is TT and heterozygous which is Tt, so the gametes will be formed would be - T and T by true tall plant and T, and t allele by heterozygous plant.
The Punnett square of this cross is attached with the answer, where 2 heterozygous offspring and two tall offspring produced. In which there is only two recessive short allele formed in this generation out of 8 alleles.
So the probability of short allele would be:
= (2/8) *100
= (1/4) *100
= 25%
