Answer:
December 31
Dr Pension expense $182,100
Cr Unfunded pension Liabiltiy $182,100
January 15
Dr Unfunded pension Liabiltiy $182,100
Cr Cash $182,100
Explanation:
Preparation of the entry to record the accrued pension liability payment to the funding agent on January 15
December 31
Dr Pension expense $182,100
Cr Unfunded pension Liabiltiy $182,100
(Being to record quarterly pension Liabiltiy)
January 15
Dr Unfunded pension Liabiltiy $182,100
Cr Cash $182,100
( Being to record the accrued pension liability payment to the funding agent)
The stock is now trading at $52.16 per share.
The current value of an annuity of n regular payments of P at r% with yearly payments is provided by:
PV = P × (1 -(
÷r))
Estes Park Corp. distributes a fixed rate of a dividend of P = $7.80 per share on its shares. The corporation will retain this dividend for the following n = 13 years before ceasing dividend payments permanently. If the necessary returns on this stock are not metis r = 11.2% = 0.112.
The actual share price is calculated as follows:
Current share price = $7.80 × (1 -(
÷0.112))
$7.80 × ((1 - 0.251) ÷ 0.112)
$52.16
Therefore, the current share price is $52.16
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Answer: It can be deduced that it's unethical for your employees to use their work computers for personal activities?
Explanation:
What is ethics?
It should be noted that ethics simply means the principle of knowing what is right from what is wrong.
In this case, it's unethical for your employees to use their work computers for personal activities. This isn't appropriate.
Furthermore, it's ethical for you to monitor computer usage. This is necessary to checkmate the activities of the employees.
If a government chooses to do this, the reduction in pollution will TAKE PLACE IN THE FIRMS WHERE ITS LEAST EXPENSIVE TO DO SO. If a government desire to establish a marketable permit program, it must first define the pollutants that will be allowed and their overall amounts that will be permissible. Companies that will mostly participate in the program will be those that do not produce much pollutants.
Answer: 0.8186
Explanation:
Given that;
activity To Tm Tp Te (V)^0.5 v
A 38 50 62 50 4 16
B 90 99 108 99 3 9
C 70 80 90 80 3.333333 11.11111
D 19 25 31 25 2 4
E 91 100 115 101 4 16
F 62 65 68 65 1 1
Expected duration Te = (4 × Tm + To + Tp ) / 6
Variance = ( Tp-To/6]²
variance of the critical path = 9+16 =25
SD of the critical path = ( var)^0.5 = 5
probability that the project will be completed within 210 days is given by
z = (210-200) / 5 = 2
which gives probability of 0.97725
Probability that the project will be completed within 195 days
z = (195-200) / 5 = -1
which corresponds to probability of 0.1586
Now required probability that project completes within 210 but before 195 days is given by
0.97725 - 0.1586 = 0.8186