Answer:
Hence the probability of the at least 9 of 10 in working condition is 0.3630492
Step-by-step explanation:
Given:
total transistors=100
defective=20
To Find:
P(X≥9)=P(X=9)+P(X=10)
Solution:
There are 20 defective and 80 working transistors.
Probability of at least 9 of 10 should be working out 80 working transistors
is given by,
P(X≥9)=P(X=9)+P(X=10)
<em>{80C9 gives set of working transistor and 20C1 gives 20 defective transistor and 100C10 is combination of shipment of 10 transistors}</em>
P(X≥9)=
<em>(Use the permutation and combination calculator)</em>
P(X≥9)=(231900297200*20/17310309456440)
+(1646492110120/17310309456440)
P(X≥9)=0.267933+0.0951162
P(X≥9)=0.3630492
Answer:
Your answer is -3
Step-by-step explanation:
I had this on a test and i got it
plz mark brainliest
Answer:
There are 96 ways different 4 digit numbers which can be made from these 5 digits.
Step-by-step explanation:
There are 5 different digits. The first one must be
1 3 5 or 7
So you can have 4 for the first one. Now the zero can be put into the mix.
4 * 4 * 3 * 2
96
C. 2x + 3
You have many ways to solve this!
You could...
A) multiply all the answer choices by 3x-2 and see what matches
B) Factor the trinomial
C) Divide the trinomial by the binomial using long division
Answer:
4) VW= 23
5) VW= 12
6) VW= 75
Step-by-step explanation:
4)
VU= 31
WU= 8
subtract 8 from 31
VW= 23
5)
UW= 18
UV= 6
subtract 6 from 18
VW= 12
6)
UV= 30
WU=45
add 30 and 45
VW= 75
