All categories

3 years ago

Please help on number 20!

Mathematics

2 answers:

valkas [14]3 years ago

8 0

Pi =π = 3.14 (for further reference)
3.14 x 10.4 = 32.67 cm is the answer. good luck!!

Tom [10]3 years ago

7 0

Answer: 32.67 cm

Explanation:

Circumference = πD
Circumference = π(10.4)
Circumference = 32.67 cm

You might be interested in

A hemisphere has a curved surface area of 364.5*22/7. Find its radius.

Stella [2.4K]

Answer:

nkvndkfhbkbhjbdhbhbfdhbkxcx

Step-by-step explanation:

vchdksbkfgbkbkhbdhbbhbshbfhklkgfsfg

6 0

3 years ago

Read 2 more answers

A single serving of jello requires 1/8 cups of sugar. How much sugar is needed for 6 servings?

sp2606 [1]

Hi there!

3/4 of sugar is needed for 6 servings.

1/8 x 6 = 6/8 simplify it and you get 3/4.

So 3/4 is your answer.

Hope this helps ;D

7 0

3 years ago

Read 2 more answers

Find the standard form of the equation of the parabola with a focus at (0, -9) and a directrix y = 9.

ololo11 [35]

The Standard Form Is

x^2 = 0 (y - 9)

5 0

3 years ago

Read 2 more answers

Which of the following does not describe slope?

Hoochie [10]

C so a proportional relationship

4 0

3 years ago

Read 2 more answers

How would I do the steps to solve this?

allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

$R(p) = -10p^2+800p$

Taking derivative wrt p

$\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\$

Now putting R'(p) = 0

$-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40$

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

$R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000$

The maximum revenue is 16000 dollars (at p = 40)

3 0

3 years ago