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2 years ago

9

Find the coordinates of the midpoint of the segment with the given endpoints.

1 answer:

uysha [10]2 years ago

8 0

$(\frac{x_{1} + y_{1}}{2}, \frac{x_{2} + y_{2}}{2}) \\(\frac{6 + 10}{2}, \frac{-3 + 5}{2}) \\(\frac{16}{2}, \frac{2}{2}) \\(8, 1)$

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A central angle θ in a circle with a radius of 6.4 centimeters intercepts an arc with a length of 8 centimeters. What is the rad

vlada-n [284]

Radius of the circle = r = 6.4 cm
Length of the arc = s = 8 cm
Measure of angle formed by the arc = <span>θ = ?

The radius of the circle, arc length and the angle made by the arc at the center of the circle are related by the equation:

s = r</span><span>θ

From here we can find </span><span>θ by:

</span><span>θ = s/r

Using the values, we get:

</span><span>θ = 8/6.4
</span><span>
θ</span><span>= 1.25 radians

Thus the radian measure of the angle </span>θ made by the arc will be 1.25 radians

7 0

3 years ago

What’s the distance between the two points in simplest radical form R(-8,-3) and S(-1,-4)

sergejj [24]

Answer:

5 $\sqrt{2}$

Step-by-step explanation:

Calculate the distance d using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 8, - 3) and (x₂, y₂ ) = (- 1, - 4)

d = $\sqrt{(-1+8)^2+(-4+3)^2}$

= $\sqrt{7^2+(-1)^2}$

= $\sqrt{49+1}$ = $\sqrt{50}$ = $\sqrt{25(2)}$ = 5 $\sqrt{2}$

6 0

3 years ago

frosja888 [35]

We have been given an equation $gv=-3x +5$ . We are asked to solve our given equation for x.

First of all, we will separate expression with x on one side of equation. We can do it by subtracting 5 from both sides of equation.

$gv-5=-3x +5-5$

$gv-5=-3x$

Now we will switch the sides as:

$-3x=gv-5$

Now we will divide both sides by $-3$ as:

$\frac{-3x}{-3}=\frac{gv-5}{-3}$

$x=-\frac{gv-5}{3}$

Therefore, the value of x would be $-\frac{gv-5}{3}$ .

4 0

3 years ago

Read 2 more answers

Find the measure of ∠u given that p||q.

abruzzese [7]

Answer:

u=y

u=35°

hope this is enough

7 0

2 years ago

School A has 216 students and 12 classrooms school B has 104 students and 4 classrooms

Gemiola [76]

Both combined would have 320 students and 16 classrooms in total but I think this is irelavent as that this isn't even a question, it's a statement.

3 0

3 years ago