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3 years ago

How many liters are in 2.751 ounces?

Mathematics

1 answer:

ivann1987 [24]3 years ago

6 0

9.30224 x 101 Ounces

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Find the length of X in simplest radical form with a rational denominator

Darya [45]

Answer:

$x = \sqrt 6$

Step-by-step explanation:

Given

The attached triangle

Required

Find x

Considering angle 30 degrees,

$Opposite = \sqrt{2$

$Adjacent = x$

Using the tangent formula:

$tan\ 30 = \frac{\sqrt 2}{x}$

Make x the subject

$x = \frac{\sqrt 2}{tan\ 30}$

$x = \frac{\sqrt 2}{1/\sqrt 3}$

$x = \sqrt 2 * \sqrt 3$

$x = \sqrt 6$

6 0

3 years ago

Keiko received an $80 gift card for a coffee store. She used it in buying some coffee that cost $8.04 per pound. After buying th

Kryger [21]

Answer:

6 pounds of coffee.

Step-by-step explanation:

First, we determine how much money she spent. 80-31.76 = 48.24

Next, we divide the money spent by the price per unit. 48.24/8.04=6

Therefore, she bought 6 pounds of coffee.

3 0

3 years ago

Read 2 more answers

What is the product of 3x+4 and 6x^{2} −5x+7?

LUCKY_DIMON [66]

$(3x + 4)(6 {x}^{2} - 5x + 7) \\ = 18 {x}^{3} - 15 {x}^{2} + 21x + 24 {x}^{2} - 20x + 28 \\ = 18 {x}^{3} + 9 {x}^{2} + x + 28$

I hope I helped you^_^

8 0

3 years ago

A food packet is dropped from a helicopter and is modeled by the function f(x) = −15x2 + 6000. The graph below shows the height

melisa1 [442]

General Idea:

Domain of a function means the values of x which will give a DEFINED output for the function.

Applying the concept:

Given that the x represent the time in seconds, f(x) represent the height of food packet.

Time cannot be a negative value, so

$x\geq 0$

The height of the food packet cannot be a negative value, so

$f(x)\geq 0$

We need to replace $-15x^2+6000$ for f(x) in the above inequality to find the domain.

$-15x^2+6000\geq 0 \; \; [Divide \; by\; -15\; on\; both\; sides]\\ \\ \frac{-15x^2}{-15} +\frac{6000}{-15} \leq \frac{0}{-15} \\ \\ x^2-400\leq 0\;[Factoring\;on\;left\;side]\\ \\ (x+200)(x-200)\leq 0$

The possible solutions of the above inequality are given by the intervals $(-\infty , -2], [-2,2], [2,\infty )$ . We need to pick test point from each possible solution interval and check whether that test point make the inequality $(x+200)(x-200)\leq 0$ true. Only the test point from the solution interval [-200, 200] make the inequality true.