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Alenkasestr [34]
3 years ago
12

What is the measure of DAB in the parallelogram ABCD

Mathematics
1 answer:
kicyunya [14]3 years ago
5 0
AFD = 49
49 + 58 = 108
DAF = 180 - 108 = 72

BFD = 180 - 49 = 131
131 + 20 = 151
BAF = 180 - 151 = 29

DAB = 29 + 72 = 101
DAB = 101
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Life Expectancies In a study of the life expectancy of people in a certain geographic region, the mean age at death was years an
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Answer:

The probability that the mean life expectancy of the sample is less than X years is the p-value of Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}, in which \mu is the mean life expectancy, \sigma is the standard deviation and n is the size of the sample.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

We have:

Mean \mu, standard deviation \sigma.

Sample of size n:

This means that the z-score is now, by the Central Limit Theorem:

Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

Find the probability that the mean life expectancy will be less than years.

The probability that the mean life expectancy of the sample is less than X years is the p-value of Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}, in which \mu is the mean life expectancy, \sigma is the standard deviation and n is the size of the sample.

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2 years ago
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Answer:

B

Step-by-step explanation:

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ivann1987 [24]

Jim's 3% commission is

... 3% × $270,000 = $8100


When that amount is added to the bonus he gets from the listing client, the total is

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3 years ago
a recent study by a researcher found that 82% of teenagers have used cellphones while driving a vehicle.suppose a random sample
melomori [17]

The probability that the sample proportion is less than 0.80 is mathematically given as P(z<-0.52)

<h3>What is the probability that the sample proportion is less than 0.80?</h3>

Generally, the equation for probability is  mathematically given as

p=82/100

Therefore

p=0.82

q=1-p

q=1-0.82

q=0.18

SE=\sqrt{\frac{p(1-p)}{n}}\\\\SE=\sqrt{\frac{0.8(1-0.8)}{100}}\\\\SE=0.03841

b)

P(p < 0.80)=p(\frac{p-0.82}{0.0384} < \frac{0.8-0.82}{0.0384})\\\\P(z < -0.52)

Read more about probability

brainly.com/question/11234923

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2 years ago
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