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3 years ago

What is the measure of DAB in the parallelogram ABCD

Mathematics

1 answer:

kicyunya [14]3 years ago

5 0

AFD = 49
49 + 58 = 108
DAF = 180 - 108 = 72

BFD = 180 - 49 = 131
131 + 20 = 151
BAF = 180 - 151 = 29

DAB = 29 + 72 = 101
DAB = 101

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Given f(x)=2x+4 and g(x)=x2−4, determine the value of (5) + (−3).

Irina18 [472]

Answer:

None of the above, f(5) + g(-3) = 19.

Step-by-step explanation:

Given f(x)=2x+4 and g(x)=x2−4, determine the value of (5) + (−3). Assume that is supposed to be f(5) + g(-3).

f(5) + g(-3) = 2×5 + 4 + (-3)^2 - 4

= 10 + 4 - 4 + (-1)^2(3)^2

= 19

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3 years ago

Read 2 more answers

A path 5m wide is to be built along the border and inside a square garden of side 90m. Find the cost of cementing the path at th

gizmo_the_mogwai [7]

Answer:

Total cost of cementing the path = Rs. 17,000.

Step-by-step explanation:

Let the square garden be ABCD

Let the region inside the garden (ABCD) be WXYZ.

Given the following data;

Length of sides of ABCD = 90m

Width of path = 5m

Cost = Rs. 10 per m²

Area of ABCD = 90 * 90

Area of ABCD = 8100m²

To find the area of WXYZ;

WX = WZ = 90 - (5 + 5)

WX = WZ = 90 - 10

WX = WZ = 80m

Area of WXYZ = WX * WZ

Substituting into the equation, we have;

Area of WXYZ = 80 * 80

Area of WXYZ = 6400 m²

Area of path = Area of ABCD - Area of WXYZ

Area of path = 8100 - 6400

Area of path = 1700 m²

Total cost of cementing the path = Area of path * cost

Total cost of cementing the path = 1700 * 10

Total cost of cementing the path = Rs. 17,000

6 0

3 years ago

At 106°F, a certain insect chirps at a rate of 67 times per minute, and at 108°F, they chirp 83 times per minute. Write an equat

Step2247 [10]

Answer:

$y=8x-781$

Here, $x$ represents temperature and $y$ denotes rate of chirping per minute.

Step-by-step explanation:

Let $x$ represents temperature and $y$ denotes rate of chirping per minute.

At $106$ °F, a certain insect chirps at a rate of $67$ times per minute.

Take $(x_1,y_1)=(106,67)$

At $108$ °F, they chirp $83$ times per minute.

Take $(x_2,y_2)=(108,83)$

Slope intercept form:

$y-y_1=(\frac{y_2-y_1}{x_2-x_1})(x-x_1)$

$y-67=(\frac{83-67}{108-106})(x-106)\\\\y-67=(\frac{83-67}{108-106})(x-106)\\\\y-67=(\frac{16}{2})(x-106)\\\\y-67=8(x-106)\\y-67=8x-848\\y=8x+67-848\\y=8x-781$

3 0

3 years ago

3. Which is the inverse of the function f(x) = 4x^2?

natali 33 [55]

Answer:

$f^{-1}(x)=\frac{\sqrt{x}}{4}$

Step-by-step explanation:

The inverse of the function is the "opposite" of a function, so to speak. One can find it by treating it like a literal equation with 2 variables, one now has to solve for the other variable presnet. In other words, treat the therm (f(x)) like another variable in the equation. Now one has to solve for (x) in terms of (f(x)).

$f(x)=4x^{2}\\$