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Marrrta [24]
2 years ago
13

Find the 90th term of the arithmetic sequence, 8.9, 13.6, 18.3, 23, …

Mathematics
1 answer:
Ronch [10]2 years ago
4 0

Answer:427.2

Step-by-step explanation:

8.9 13.6 18.3

it goes up in 4.7

4.7n

8.9-4.7=4.2

4.7n+4.2

4.7(90)+4.2

423+4.2=427.2

Hopefully it is correct :)

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there is also a D is its not any just say none so i know its d pls dont joke ima get kicked out the class is i dont do good​
Monica [59]

Answer:

b

Step-by-step explanation:

son

8 0
3 years ago
What is the base five representation of The number 219
ICE Princess25 [194]

assuming 219_{10}

Then the column values for base five here are

5³  5²  5^{1}  5^{0}

We can get 1 × 5³ = 125 → 219 - 125 = 94

We can get 3 × 5² = 75 → 94 - 75 = 19

We can get 3 x 5^{1} → 19 - 15 = 4

and 4 = 4 × 5^{0}

Thus 219_{10} = 1334_{5}

As a check

(1 × 125 ) + (3 × 25 ) + (3 × 5 ) + 4 = 219


3 0
3 years ago
out of a senior class of 100 students the.class offers (president vice president treasurer needs to be arranged.com how many dif
kondaur [170]
Answer: 33

explanation: 100/3 = 33.333, and since it isn't possible for 0.333 to be three different students being picked, there are only 33 different ways.
8 0
2 years ago
10tu^3 + 4v - 3v<br><br> must combine like terms solve or rewrite expression
pshichka [43]

10tu³ + v is the simplified form.

<h3>What is algebraic expression?</h3>

A number, a variable, or a mix of numbers, variables, and operation symbols make up an expression. Two expressions joined by an equal sign form an equation. Word illustration: The product of 8 and 3. Word illustration: The product of 8 and 3 is 11

to learn more about algebraic expression refer to:

brainly.com/question/4344214

#SPJ9

5 0
2 years ago
Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 75.6 Mbp
olga55 [171]

Answer:

a) 59.98

b) 2.99

c) 2.99

d) Significantly High

Step-by-step explanation:

Part a)

Highest speed measured = x = 75.6 Mbps

Average/Mean speed = \overline{x} = 15.62 Mbps

Standard Deviation = s = 20.03 Mbps

We need to find the difference between carrier's highest data speed and the mean of all 50 data​ speeds i.e. x - \overline{x}

x - \overline{x} = 75.6 - 15.62 = 59.98 Mbps

Thus, the difference between​ carrier's highest data speed and the mean of all 50 data​ speeds is 59.98 Mbps

Part b)

In order to find how many standard deviations away is the difference found in previous part, we divide the difference by the value of standard deviation i.e.

\frac{59.98}{20.03}=2.99

This means, the difference is 2.99 standard deviations or in other words we can say, the Carrier's highest data speed is 2.99 standard deviations above the mean data speed.

Part c)

A z score tells us that how many standard deviations away is a value from the mean. We calculated the same in the previous part. Performing the same calculation in one step:

The formula for the z score is:

z=\frac{x-\overline{x}}{s}

Using the given values, we get:

z=\frac{75.6-15.62}{20.03}=2.99

Thus, the Carriers highest data is equivalent to a z score of 2.99

Part d)

The range of z scores which are neither significantly low nor significantly​ high is -2 to + 2. The z scores outside this range will be significant.

Since, the z score for carrier's highest data speed is 2.99 which is well outside the given range, i.e. greater than 2, we can conclude that the  carrier's highest data speed​ is significantly higher.

3 0
3 years ago
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