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loris [4]
3 years ago
8

How do i construst a histogram?

Mathematics
1 answer:
icang [17]3 years ago
4 0

A histogram is like a bar graph without gaps between the rectangles. So you first create a bar graph with your labels and title, then you get rid of the gaps between the rectangles.

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Fundraising The robotics team needs new uniforms. The students plan to sell plush toy lions ​(the school​ mascot) for​ $5 each.
nataly862011 [7]

Answer:

Company C!

Step-by-step explanation:

In order to see which company has the best buy  we have to see the amount each company sells for one stuffed mascot. In order to do this we have to divide .

Company A:

Company A sells 16 lions for $44.32 this is the same as 1 stuffed lion for $2.77.

Company B:

Company B sells 18 lions for $50.22 this is the same as 1 stuffed lion for  $2.79.

Company C:

Company C sells 12 lions for $32.88 this is the same as 1 stuffed lion for $2.74

Thus as you can see the company with the best buy is company C.

8 0
3 years ago
Read 2 more answers
Stacey and Jeremy sent out 380 wedding invitations. They have received 127 responses. What does q represent in the equation 380
alexandr402 [8]
Q=253, which is the number of responses they have not received
5 0
3 years ago
Read 2 more answers
Find the area, please help me, having a hard time getting through tonight’s homework. Complex/Compound area. Thanks!
Digiron [165]
Since the bottom shape is a semi-circle, the 3yd is the radius making the triangle's area 7 x 3 / 2 = 10.5

The semi-circle's area is \pi 3^{2} /2 = 14.14

Combined, you get an area of 10.5 + 14.14 = 24.64yd^{2}
7 0
3 years ago
The Quality Control Department employs five technicians during the day shift. Listed below is the number of times each technicia
sveta [45]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

Technician __Shutdown

Taylor, T___4

Rousche, R _ 3

Hurley, H__ 3

Huang, Hu___2

Gupta, ___ 5

The Numbe of samples of 2 possible from the 5 technicians :

We use combination :

nCr = n! ÷ (n-r)!r!

5C2 = 5!(3!)2!

5C2 = (5*4)/2 = 10

POSSIBLE COMBINATIONS :

TR, TH, THu, TG, RH, RHu, RG , HHu, HG, HuG

Sample means :

TR = (4+3)/2 = 3.5

TH = (4+3)/2 = 3.5

THu = (4+2) = 6/2 = 3

TG = (4 + 5) = 9/2 = 4.5

RH = (3+3) = 6/2 = 3

RHu = (3+2) /2 = 2.5

RG = (3 + 5) = 8/2 = 4

HHu = (3+2) = 2.5

HG = (3+5) = 8/2 = 4

HuG = (2+5) / 2 = 3.5

Mean of sample mean (3.5+3.5+3+4.5+3+2.5+4+2.5+4+3.5) / 10 = 3.4

Population mean :

(4 + 3 + 3 + 2 + 5) / 5 = 17 /5 = 3.4

Population Mean and mean of sample means are the same.

This distribution should be approximately normal.

7 0
3 years ago
Someone help me please and thank you!! ASAP :(
pantera1 [17]
<h3>Answer: Choice D) </h3>

Work Shown:

(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\

We must require that x \ne -12 and x \ne 3 to avoid having 0 in the denominator. This is why choice D is the answer.

3 0
3 years ago
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