All categories

3 years ago

How do i construst a histogram?

1 answer:

4 0

A histogram is like a bar graph without gaps between the rectangles. So you first create a bar graph with your labels and title, then you get rid of the gaps between the rectangles.

You might be interested in

Please answer this question now in two minutes

kykrilka [37]

Answer:

$y=\frac{3}{2}x+4$

Step-by-step explanation:

So the line C equation is $y=\frac{3}{2}x+2$ and line D is parallel to it and it passes through the point (4,10) and we need to ding the equation for line D.

So first we have a graph with line C listed and (4,10).

And we can keep listing more equations till we find the right one which is $y=\frac{3}{2}x+4$ .

So I got this by knowing that in parrelel lines the slope is the same but the y intercept changes which is why it was fast to find the answer.

7 0

4 years ago

Read 2 more answers

How do you add on 10% of £1,200how do you add on 10% of £1,200

mars1129 [50]

First find 10%
(1200 divided by 10)
10% = £120
Then add it onto the original amount
£1200 + £120 = £1320

3 0

3 years ago

What is the root of the function f(x)=3x^2-21x?

GrogVix [38]

Answer: The root of this function would be (7,0)

8 0

3 years ago

The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days. a. Find the pro

MrMuchimi

Answer:

a. 0.313% (0.003134842261), b. 237.79 days (237.788095878)

Step-by-step explanation:

In this case, the length of pregnancies is a normally distributed variable, with a mean of 266 days, and a standard deviation of 15 days.

A graph showing the distribution, with regions of interest for the answer, is presented below.

<h3>First Part: Find the probability of a pregnancy lasting 307 days or longer.</h3>

To answer the question regarding <em>the probability of a pregnancy lasting 307 days or longer</em>, it is necessary to calculate what the cumulative probability distribution value is at 307 days. By the way, according to the graph below, 307 days are quite far from the population mean (266 days).

Using the function <em>normaldist(266,15).cdf(307)</em>, from free Desmos software on Internet, we find that, at this length (307 days), the sum of all probabilities for all cases at this value is 99.69% (0.996865157739).

Considering that the total area of the curve is 1, then <em>the probability of pregnancy lasting 307 days or longer</em> is 1 - 0.996865157739 or 0.003134842261 (or 0.00313), approximately 0.313%, a very low probabilty.

This probability is showed as the "light blue" region at the right extreme of the graph.

<h3>Second Part: Find the length that separates premature babies from those who are not premature.</h3>

To find the length that separates premature babies from those who are not premature, it is a question about <em>find the days related with the probability of 3% (or 0.03)</em> to find such premature babies. So, it is a question of finding a percentile (or 100-quantiles): given the cumulative normal distribution curve, what is the value (length of pregnancies) that represents this 3%.

Using the function <em>quantile(normaldist(266,15), 0.03)</em>, from free Desmos software on Internet, we obtained a value of 237.79 days (237.788095878) for the length of pregnacies of premature babies. In other words, those babies whose mothers have a length of pregnancy <em>lower</em> than 237.79 days are considered premature, or this is "the length that separates premature babies from those who are not premature".

The area below 237.79 days is the blue shaded region in the graph below, at the left extreme of it.

4 0

3 years ago

Read 2 more answers

A square has an area of 121 in^2 what is the length of the sides

Gelneren [198K]

Answer:

11in

Step-by-step explanation:

$\sqrt[]{121} =11$ Then you add the units.

6 0

3 years ago