A or B or C or D <br> ???????????

You are given a problem that involves multiplying a positive number and a negative number.

kenny6666 [7]

Answer:

-3 and -2

Step-by-step explanation:

A better explanation...

(positive)(positive)= positive

(positive)(negative)= negative

(negative)(negative)= positive

(negative)(positive)= negative

3 0

3 years ago

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80 pts!!! Plz answer me will mark as brainliest

nignag [31]

Answer:

Step-by-step explanation:

The numbers 0 and 1 are neither prime nor composite. They are too special because they represent nothingness (zero) and wholeness (one), so the idea of having factors for 0 and 1 does not make sense. ... For example, all even numbers are divisible by two, and so all even numbers greater than two are composite numbers.if a natural number is not prime, then we say that it is composite. ... Example: The value six, 6, is a composite number because it has four counting number factors: 1, 2, 3, and 6. We have 1 · 6 = 6 and 2 · 3 = 6. It turns out that mathematicians have declared that 1 is neither prime nor composite.

6 0

3 years ago

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Students were asked to write 6x + Xx - 3x +

Anastasy [175]

Answer:

Sorry

Step-by-step explanation:

Where are the answer of the four students?

7 0

3 years ago

What is a qualitative prediction?

d1i1m1o1n [39]

A qualitative prediction is made by using senses and educated guesses, unlike quantitative observations which use scientific methods. For example, you take a rock and examine it. One qualitative observation of this rock is it is smooth and gray. A quantitative observation is it is two pounds.
Hope I helped :))

7 0

2 years ago

I tell you these facts about a mystery number, $c$: $\bullet$ $1.5 < c < 2$ $\bullet$ $c$ can be written as a fraction wit

makkiz [27]

Answer:

Possible answer: $\displaystyle c = \frac{16}{10} = \frac{8}{5} = 1.6$ .

Step-by-step explanation:

Rewrite the bounds of $c$ as fractions:

The simplest fraction for $1.5$ is $\displaystyle \frac{3}{2}$ . Write the upper bound $2$ as a fraction with the same denominator:

$\displaystyle 2 = 2 \times 1 = 2 \times \frac{2}{2} = \frac{4}{2}$ .

Hence the range for $c$ would be:

$\displaystyle \frac{3}{2} < c < \frac{4}{2}$ .

If the denominator of $c$ is also $2$ , then the range for its numerator (call it $p$ ) would be $3 < p < 4$ . Apparently, no whole number could fit into this interval. The reason is that the interval is open, and the difference between the bounds is less than $2$ .

To solve this problem, consider scaling up the denominator. To make sure that the numerator of the bounds are still whole numbers, multiply both the numerator and the denominator by a whole number (for example, 2.)

$\displaystyle \frac{3}{2} = \frac{2 \times 3}{2 \times 2} = \frac{6}{4}$ .

$\displaystyle \frac{4}{2} = \frac{2\times 4}{2 \times 2} = \frac{8}{4}$ .

At this point, the difference between the numerators is now $2$ . That allows a number ( $7$ in this case) to fit between the bounds. However, $\displaystyle \frac{1}{c} = \frac{4}{7}$ can't be written as finite decimals.

Try multiplying the numerator and the denominator by a different number.

$\displaystyle \frac{3}{2} = \frac{3 \times 3}{3 \times 2} = \frac{9}{6}$ .

$\displaystyle \frac{4}{2} = \frac{3\times 4}{3 \times 2} = \frac{12}{6}$ .

$\displaystyle \frac{3}{2} = \frac{4 \times 3}{4 \times 2} = \frac{12}{8}$ .

$\displaystyle \frac{4}{2} = \frac{4\times 4}{4 \times 2} = \frac{16}{8}$ .

$\displaystyle \frac{3}{2} = \frac{5 \times 3}{5 \times 2} = \frac{15}{10}$ .

$\displaystyle \frac{4}{2} = \frac{5\times 4}{5 \times 2} = \frac{20}{10}$ .

It is important to note that some expressions for $c$ can be simplified. For example, $\displaystyle \frac{16}{10} = \frac{2 \times 8}{2 \times 5} = \frac{8}{5}$ because of the common factor $2$ .

Apparently $\displaystyle c = \frac{16}{10} = \frac{8}{5}$ works. $c = 1.6$ while $\displaystyle \frac{1}{c} = \frac{5}{8} = 0.625$ .

8 0

3 years ago

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A or B or C or D ???????????