Answer:
Y=19 Hope this helps!!!!
Step-by-step explanation:
For question number 1:The plot H = H(t) is the parabola and it reaches its maximum in the moment when exactly at midpoint between the roots t = 0 and t = 23. At that moment t = 23/2 or 11.5 seconds.
For question number 2:To find the maximal height, just simply substitute t = 11.5 into the quadratic equation. The answer would be 22.9.
For question number 3:H(t) = 0, or, which is the same as -16t^2 + 368t = 0.Factor the left side to get -16*t*(t - 23) = 0.t = 0, relates to the very start of the process, when the ash started its way up.The other root is t = 23 seconds, and it is precisely the time moment when the bit of ash will go back to the ground.
Answer:
i think 126 different bowls
correct me if im wrong
Answer:
The answer is <u>D. quadrilaterals</u>
Step-by-step explanation:
- <u><em>All </em></u><u><em>trapezoids </em></u><u><em>are squares. If a shape is a square, then it is also a rectangle and a rhombus. A</em></u><u><em> trapezoid </em></u><u><em>is a </em></u><u><em>quadrilateral </em></u><u><em>with exactly one set of parallel sides</em></u>