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Alenkinab [10]
3 years ago
15

Find the equation of a line that is parallel to y=x+3 and passes through the point (-2,-4)

Mathematics
1 answer:
Dafna1 [17]3 years ago
5 0

Answer:

y = x - 2

Step-by-step explanation:

y + 4 = 1 (x + 2)

y + 4 = x + 2

y = x - 2

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Okay I don't understand how do I do this. It say :
Lilit [14]

2x+3=17

subtract 3 from each side

2x+3 -3 = 17 -3

2x = 14

divide by 2 on each side

2x/2 = 14/2

x = 7

6 0
3 years ago
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Find y so that (-2, y) is a solution to 3x + 5y=8​
podryga [215]

Answer:

y = \frac{14}{5}

Step-by-step explanation:

Substitute x = - 2 into the equation and solve for y

3(- 2) + 5y = 8, that is

- 6 + 5y = 8 ( add 6 to both sides )

5y = 14 ( divide both sides by 5 )

y = \frac{14}{5}

5 0
3 years ago
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Furkat [3]
Number 1 is 0.2 and 0.4
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4 0
3 years ago
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a news report say that 28% of high school students pack their lunch. your high school has 600 students. how many students in you
Rama09 [41]

28 % is actually written as .28 , so it would be written like this ,  600 * 28 = 168.00 = for more simplified form it would be , 168 students    ,  hope this helps
7 0
3 years ago
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Suppose f is a one-to-one function with f(2)=8 and f’(2)=4. What is the value of (f^-1)’(8)?
yuradex [85]

Answer:

1/4

Step-by-step explanation:

The tangent line to f(x) at x=2 goes through the point (2, 8) and has slope 4.

The inverse function f⁻¹(x) is a reflection of the function f(x) across the line y=x. The corresponding tangent line will go through point (8, 2) and have slope 1/f'(2) = 1/4 at that point. That is, ...

(f⁻¹)'(8) = 1/f'(f⁻¹(8)) = 1/f'(2) = 1/4

5 0
3 years ago
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