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IgorC [24]
3 years ago
10

victor borrowed $21.50 from his mother to go to the theater.A week later he paid her $21.50 back. how do he still owe her?

Mathematics
1 answer:
Tresset [83]3 years ago
7 0

He owns his mother $0; Because $21.50 - $21.50 is Zero

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Is two over five irrational numbers
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Answer:

No, It is not irrational number.

Step-by-step explanation:

2/5 is a rational number. A rational number is a number of the form q/q where p and q are integers and q is not equal to 0.

4 0
3 years ago
A single die is rolled twice. Find the probability of rolling an even number the first time and a number greater than 3 the seco
IceJOKER [234]

Events

• A: an even number is rolled in the first time

,

• B: a number greater than 3 is rolled the second time

The probability of rolling an even number is:

\begin{gathered} P(A)=\frac{\text{ number of favorable outcomes}}{\text{ total possible outcomes}} \\ P(A)=\frac{3}{6} \\ P(A)=\frac{1}{2} \end{gathered}

The probability of rolling a number greater than 3 is:

\begin{gathered} P(B)=\frac{\text{ number of favorable outcomes}}{\text{ total possible outcomes}} \\ P(B)=\frac{3}{6} \\ P(B)=\frac{1}{2} \end{gathered}

Events A and B are independent, then the probability of one happening after the other is:

\begin{gathered} \text{ P(A and B) = }P(A)\cdot P(B) \\ \text{ Substituting with the values previously found:} \\ \text{ P(A and B) = }\frac{1}{2}\cdot\frac{1}{2} \\ \text{ P(A and B) = }\frac{1}{4} \end{gathered}

8 0
1 year ago
which one are true for this 4+2x.. a two variables b. is a product c. the coefficient of x is 4.. d 4+2x is a sum​
Nutka1998 [239]

Answer:

b

Step-by-step explanation:

4 0
2 years ago
I really need help with this and if you don't know it says which one is NOT
Natasha_Volkova [10]
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3 0
3 years ago
Read 2 more answers
Solve the initial-value problem<br><br> y' = x^4 - \frac{1}{x}y, y(1) = 1.
natta225 [31]

The ODE is linear:

y'=x^4-\dfrac yx

y'+\dfrac yx=x^4

Multiplying both sides by x gives

xy'+y=x^5

Notice that the left side can be condensed as the derivative of a product:

(xy)'=x^5

Integrating both sides with respect to x yields

xy=\dfrac{x^6}6+C

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Since y(1)=1,

1=\dfrac16+C\implies C=\dfrac56

so that

\boxed{y(x)=\dfrac{x^5}6+\dfrac5{6x}}

4 0
3 years ago
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