Answer:
B) 2.849
Step-by-step explanation:
Given: 2.85 which is rounded to the nearest hundredth place.
To find the number, the thousandth place must be greater than or equal to 5.
Here 2.849 has the thousandth place greater than 5
When we round off 2.849 to the nearest hundredth place, we get
2.85
Therefore, answer is B) 2.849
Hope this will helpful.
Thank you.
<h3>
Answer:</h3>
3) likely
4) 1/2; equally likely
<h3>
Step-by-step explanation:</h3>
3) You are being asked to translate a numerical value to a subjective statement. There are no hard-and-fast rules for this. Generally, the meanings of the terms you're asked to choose from are ...
- impossible: probability is zero. The outcome cannot occur.
- unlikely: chances are less than even; often, "unlikely" means a probability of 10%, 5%, 1% or lower, depending on the context.
- equally likely: probability is near 50%
- likely: more likely than not. Again, this depends on the context.
- certain: probability is 1. There is no chance the outcome will not occur.
An 80% probability is greater than 50%, so might reasonably be called "likely."
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4) a. Four of the eight numbers are even, so the probability of obtaining an even number at random is 4/8 = 1/2.
b. A probability of 50% might reasonably be called "equally likely", as the probability the event will occur is equal to the probability it won't.
∆BOC is equilateral, since both OC and OB are radii of the circle with length 4 cm. Then the angle subtended by the minor arc BC has measure 60°. (Note that OA is also a radius.) AB is a diameter of the circle, so the arc AB subtends an angle measuring 180°. This means the minor arc AC measures 120°.
Since ∆BOC is equilateral, its area is √3/4 (4 cm)² = 4√3 cm². The area of the sector containing ∆BOC is 60/360 = 1/6 the total area of the circle, or π/6 (4 cm)² = 8π/3 cm². Then the area of the shaded segment adjacent to ∆BOC is (8π/3 - 4√3) cm².
∆AOC is isosceles, with vertex angle measuring 120°, so the other two angles measure (180° - 120°)/2 = 30°. Using trigonometry, we find
where 
is the length of the altitude originating from vertex O, and so
where 
is the length of the base AC. Hence the area of ∆AOC is 1/2 (2 cm) (4√3 cm) = 4√3 cm². The area of the sector containing ∆AOC is 120/360 = 1/3 of the total area of the circle, or π/3 (4 cm)² = 16π/3 cm². Then the area of the other shaded segment is (16π/3 - 4√3) cm².
So, the total area of the shaded region is
(8π/3 - 4√3) + (16π/3 - 4√3) = (8π - 8√3) cm²
