Since 1 ton is equivalent to 2000pounds, 6000 pounds would be 3 tons.
As these triangle has two proportional sides lengths (20/5 = 4 = 12/3), and this pair of sides confines two congruent angles (<P = <S), so these two triangles are similar...
and the postulate for this is: Side-Angle-Side (SAS)
choice: D
Answer:
y/2
y*2
y-2
y+2
y%2
y^2
<h3>Operations on Algebraic Expressions: </h3>
- The three major components of an algebraic expression are variables, constants, and coefficients. Addition, subtraction, multiplication, and division are the four fundamental operations. We solve both difficult and straightforward equations using operations on algebraic expressions.
- There are three categories of algebraic expressions: monomial, binomial, and polynomial or multi-term expressions.
- These are the algebraic terms:
- Alphabetic letters alone or in combination with numbers or fractions are the variables.The numbers that are connected to the variables in a single term are called coefficients.
- Constants: Single integers or numbers that are typically connected to other terms through elementary operations.Examples include 8xyz, 25x+12y+9, 2yz23zy, and 3a+2b+5c.
Algebraic Expression Types
There are three different categories for algebraic expressions. As follows:
- Expressions with a monomial or single word. For instance, 4xy2, 3ab, 7p, 5xyz, etc., where 3,4,5,7 are the coefficients and x, y, z, a, b, p are the variables.
- Expressions with two terms or a binomial. For instance, 2xyx, pq5p2, etc.
- Multi-term or polynomial expressions. as in 2x+5y4, 2xy2+3y+1, etc.
To learn more about Operations on Algebraic Expressions refer to:
brainly.com/question/26447829
#SPJ1
<span>8!= 8*7*6*5*4*3*2*1= 40,320
It worked!<span>
</span></span>
<span>Sphere: (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100
Intersection in xy-plane: (x - 4)^2 + (y + 12)^2 = 36
Intersection in xz-plane: DNE
Intersection in yz-plane: (y + 12)^2 + (z - 8)^2 = 84
The desired equation is quite simple. Let's first create an equation for the sphere centered at the origin:
x^2 + y^2 + z^2 = 10^2
Now let's translate that sphere to the desired center (4, -12, 8). To do that, just subtract the center coordinate from the x, y, and z variables. So
(x - 4)^2 + (y - -12)^2 + (z - 8)^2 = 10^2
(x - 4)^2 + (y - -12)^2 + (z - 8)^2 = 100
Might as well deal with that double negative for y, so
(x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100
And we have the desired equation.
Now for dealing with the coordinate planes. Basically, for each coordinate plane, simply set the coordinate value to 0 for the axis that's not in the desired plane. So for the xy-plane, set the z value to 0 and simplify. So let's do that for each plane:
xy-plane:
(x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100
(x - 4)^2 + (y + 12)^2 + (0 - 8)^2 = 100
(x - 4)^2 + (y + 12)^2 + (-8)^2 = 100
(x - 4)^2 + (y + 12)^2 + 64 = 100
(x - 4)^2 + (y + 12)^2 = 36
xz-plane:
(x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100
(x - 4)^2 + (0 + 12)^2 + (z - 8)^2 = 100
(x - 4)^2 + 12^2 + (z - 8)^2 = 100
(x - 4)^2 + 144 + (z - 8)^2 = 100
(x - 4)^2 + (z - 8)^2 = -44
And since there's no possible way to ever get a sum of 2 squares to be equal to a negative number, the answer to this intersection is DNE. This shouldn't be a surprise since the center point is 12 units from this plane and the sphere has a radius of only 10 units.
yz-plane:
(x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100
(0 - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100
(-4)^2 + (y + 12)^2 + (z - 8)^2 = 100
16 + (y + 12)^2 + (z - 8)^2 = 100
(y + 12)^2 + (z - 8)^2 = 84</span>