Answer:
b should be correct
Step-by-step explanation:
you times the amount of hours by 20 and then add the 35 into the total value of 120
Answer:
b
Step-by-step explanation:
83+37=129, 120÷24=5
Answer:

(Please vote me Brainliest if this helped!)
Step-by-step explanation:


1. 

2. 

3. 
4. 
5. 
