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Eduardwww [97]
4 years ago
15

MATH- ALGEBRA 1- SHOW WORK PLEASE

Mathematics
2 answers:
Scilla [17]4 years ago
5 0
The average rate of change would be the change in y/the change in x. You must enter the x values into the function to get the corresponding y values. We’ll call x=0 x1, and we’ll call x=8 x2. y1 will be the y value corresponding to x1, and y2 will be the y value corresponding to x2. Finding the change in y would be y2–y1, and the change in x would be x2–x1.
natali 33 [55]4 years ago
5 0

Rates are essentially the same as ratios - they're comparisons of two different values by division. Our goal in finding a rate is to find how the two values involved relate to each other, and in this problem, we want to find how much some <em>change in x </em>relates to some <em>change in f(x)</em>. By convention, we make this comparison by dividing the change in f(x) by the change in x, frequently written as Δf(x) and Δx. Symbolically, this looks like

\frac{\Delta f(x)}{\Delta x}

We measure the change in some value through subtraction - here, we're given the values x = 0 and x = 8, so we can subtract one from the other to say that Δx = 8 - 0 = 8.

To find Δf(x), we first need to find two appropriate values to compare. Since we're given x = 0 and x = 8, we'll choose f(0) and f(8). Here are the calculations for those:

f(0)=\frac{2(0)+3}{3(0)-3} =\frac{3}{-3} =-1

f(8) = \frac{2(8)+3}{3(8)-3}=\frac{16+3}{24-3}=\frac{19}{21}

We can then find Δf(x) by finding f(8) - f(0):

\Delta f(x)=\frac{19}{21}-(-1)=\frac{19}{21}+1=\frac{19}{21} +\frac{21}{21}=\frac{40}{21}

We can now return to our rate and substitute the values Δx = 8 and Δf(x) = 40/21 to get the ratio

\dfrac{\frac{40}{21}}{8}

since fractions are another way of writing division, and since dividing by a number is the same as multiplying by its reciprocal, we can rewrite this ratio as

\dfrac{\frac{40}{21}}{8} =\frac{40}{21}\div8=\frac{40}{21}\times\frac{1}{8}

40 and 8 have the factor 8 in common, so we can cross cancel to reduce 40 to 5 and 8 to 1 (since 40 = 8 x 5 and 8 = 8 x 1), finally giving us

\frac{40}{21}\times\frac{1}{8}=\frac{5}{21}\times\frac{1}{1}=\frac{5}{21}

which is the answer we were looking for.

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Given right triangle DEF, what is the value of tan(F)?
LiRa [457]

Answer:

if you don't give numbers how can you even find the tan of F?

Step-by-step explanation:


5 0
3 years ago
What are the solutions to the quadratic equation 98-x2=0
kifflom [539]

98-x^2=0\qquad\text{add}\ x^2\ \text{to both sides}\\\\98=x^2\to x^2=98\\\\x=\pm\sqrt{98}\\\\x=\pm\sqrt{49\cdot2}\\\\x=\pm\sqrt{49}\cdot\sqrt2\\\\\boxed{x=-7\sqrt2\ \vee\ x=7\sqrt2}

8 0
3 years ago
Suppose that a cyclist began a 374 mi ride across a state at the western edge of the​ state, at the same time that a car traveli
kherson [118]
This is the concept of relative speed; We are required to calculate the speed of the car and the bicycle.
Distance between the car and Bicycle=374 miles
Time they met=5.5 hr
Speed traveled by bicycle=x
Speed traveled by car=x+33.4334
Relative speed=x+(x+33.4334)=(2x+33.4334) mph
Distance=speed*time
374=(2x+33.4334)*5.5
374=11x+183.8837
collecting like term we get:
374-183.8837=11x
11x=190.1163
thus;
x=(190.1163)/(11)
x=17.2833 mph
thus the speed of the bicycle was x=17.2833 mph
The speed of the car was (x+33.4334)=(17.2833+33.4334)=50.7167 mph

4 0
4 years ago
Irrational numbers cannot be written as a ratio…irrational means not rational. All fractions of integers are Rational.
TiliK225 [7]

with the exception of perfect squares, all square root of whole numbers are irrational, e.g. √5

how about this one:

2.34334333433334.... I am increasing the number of 3s each time, thus

creating a decimal which never ends and never repeats.

or

12.3456789101112131415.... can you see what I am doing?

will it ever end? will it ever repeat?

3 0
3 years ago
Find how many solutions there are to the given equation that satisfy the given condition.
den301095 [7]

Answer:

17550 solutions

Step-by-step explanation:

Given that:

y1 +y2+y3+y4=27

where;

(yi  ≥ 0 and yi \epsilon {\displaystyle \mathbb {Z} }  )

The no. of a nonnegative integer determines the number of ways to choose 27 objects from (4) distinct objects with repetition regardless of the order.

i.e

\bigg(^{27}_{4} \bigg)

∴

The number of nonnegative integer solution is \bigg(^{27}_{4} \bigg)

= \dfrac{27!}{4!(27-4)!}

= \dfrac{27!}{4!(23)!}

= \dfrac{27\times 26\times 25\times 24 \times  23 !}{4\times 3\times 2\times 1(23)!}

= \dfrac{27\times 26\times 25\times 24 }{4\times 3\times 2\times 1}

= \dfrac{421200}{24}

= 17550 solutions

7 0
3 years ago
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