We have an isosceles triangle;
A=opposite angle side a.
B=opposite angle side b.
C=opposite angle side c.
A=B
Method 1:
We can divide the isosceles triangle in two right triangles,
hypotenuse=7
side=9/2=4.5
B=A=arccossine (4.5/7)=49.994799...º≈50º
C/2=90º-50º=40º ⇒ C=2*40º=80º
Answer:
a=7; A=50º
b=7; B=50º
<span>c=9; C=80º
Method 2:
Law of cosines:
a²=b²+c²-2bcCosA ⇒CosA=(a²-b²-c²)/(-2bc)
CosA=(49-49-81) / (-126)=0.642857
A=arco cos (81/126)≈50º
B=A=50º
A+B+C=180º
50º+50º+C=180º
C=180º-100º
C=80º
Answer:
</span>a=7; A=50º
b=7; B=50º
<span>c=9; C=80º</span>
2 and 1/2 gallons of paint because if 2/5 is painted with 1 gallon, then 4/5 would be 2 gallons and the last 1/5 would be half a gallon.
Answer:
the function given 
for 4 units up, just add 4 as a constant
4 units up means, every old value will now be 4 more than previous value. at x=0, y=0 in the transformed curse it should x=0 and y=4, so just add it.

for 6 units left,
each old value of y should now occur 6 units before the old value of x i.e. X=x+6
for example, the point (0,0) should occur at (-6,0) in the transformed graph,
hence, 
so the final curve is

8x + y = -16 ;
3x - y = 5 ;
____________(+)
11x = -11;
x = - 11 / 11 ;
x = - 1;
y = -5 + 3 * ( - 1 ) = - 8.