Im not sure but maybe 1 adult and one child but im not sure if this is a trick question
Answer:
P(X<1200) is 0.8212
Step-by-step explanation:
Test statistic (z) = (X - mean)/sd
X is score of a tester = 1200
mean = 1497
sd = 322
z = (1200 - 1497)/322 = -297/322 = -0.92
The cumulative area of the test statistic is the probability that X<1200. The cumulative area is 0.8212.
Therefore, P(X<1200) = 0.8212
The amount you save is : $119 (usd im so sorry, i tried to do it in £ but i had a hard time with the different currencies.) so, the sale price is : $51 usd
Alright, so we have 1.3/0.0338. Since it's easier (in my opinion) to work with whole numbers, we can multiply the fraction by 10000/10000 to get 13000/338. With a bit of guess and check, we can see that
338*30=338*3*10
1 2 (what I carry is at the top)
338
x3
____
1114
Multiplying that by 10, I get 11140, which isn't enough. Trying 338*40, which is 338*4*10, we can add 338 to 338*3 to get 338*4 to get
2
1114
+338
____
1462
Multiplying that by 10, we get 14620, which is more than 13000 - something we don't want. Repeating this for 338*35 (which is 338*3.5*10, and 3.5 is 3*338+338/2)=11830 and which isn't enough, we then move on to something between 35 and 40 (the number doesn't matter), say 39. 338*39=338*3.9*10, and 338*3.9 is 338*3+338*9/10, and
338*39 results to 13182, which is more than 13000 , but only by a tiny bit, so we can try 38 using the same method, getting 12844, which is smaller, so we know it's between 38 and 39. Finding the difference between 13000 and 12844, we get 13000-12844=156 and the answer is therefore 38+156/338
Answer:
min = a_1
for i:= 2 to n:
if 
< min then min =
return min
Step-by-step explanation:
We call the algorithm "minimum" and a list of natural numbers 
So lets first set the minimum to 
min = a_1
now we want to check all the other numbers.
We can use a simple for loop, to find the minimum
min = a_1
for i:= 2 to n:
if < min then min =
return min
