Solution :
2a + 2b = 7 ...1)
4a + 3b = 12 ...2)
In equation, 1)
a = (7 - 2b)/2 ...3)
Putting value of a in equation 2) we get :
4 × (7 - 2b)/2 + 3b = 12
2( 7 - 2b ) + 3b = 12
14 - 4b + 3b = 12
b = 2
Putting value of b in 3) we get :
a = ( 7 - 2×2)/2
a = 3/2 = 1.5
Now,
2x - 3y = 16 ...5)
x + 2y = -6 ...6)
x = -6 - 2y
Putting above value of x in eq 5) , we get :
2( -6 - 2y ) - 3y = 16
-12 - 4y - 3y = 16
7y = -28
y = -4
x = -6 - ( 2× -4 )
x = 2
Hence, this is the required solution.
Answer:
2
Step-by-step explanation:
Ok, so if we know how much wire is needed for one outlet, we must figure out how many 18.25s fit into 50 ft of wire.
18.25*2=36.5
18.25*3=54.75 which is over 50 so it cannot possibly be more than 2.
2 to the negative 1 power. When you divide two exponents with the same base, you subtract the two exponents to get your answer.
:)
Pythagora: 20^2=(4x)^2+(3x^2)
400=16x^2+9x^2
x^2=400/25
x^2=16
x=4
