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3 years ago

What is this answer?

Mathematics

2 answers:

devlian [24]3 years ago

7 0

Answer:

Step-by-step explanation:

blondinia [14]3 years ago

6 0

Ok so when u do these look to find where u can see a recangle
so the rectangle is 10x12= 120
then find the area of the shape below it which is 192 add them an get 312

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Find domain of the rational function<br><br> C(x)=-x-5/x^2-25

iren2701 [21]

$\large\begin{array}{l} \textsf{Find the domais of the rational function:}\\\\ \mathsf{C(x)=\dfrac{x-5}{x^2-25}}\\\\\\ \textsf{Denominators can't be zero:}\\\\ \mathsf{x^2-25\ne 0}\\\\ \mathsf{x^2\ne 25}\\\\ \begin{array}{rcl} \boxed{\begin{array}{rcl}\mathsf{x\ne -5}&~\textsf{ and }~&\mathsf{x\ne 5}\end{array}} \end{array} \end{array}$

$\large\begin{array}{l} \textsf{So the domain of C is}\\\\ \mathsf{D_C=\{x\in\mathbb{R}:~~x\ne -5~~and~~x\ne 5\}}\\\\\\ \textsf{or using a more compact form}\\\\ \mathsf{D_C=\mathbb{R}\setminus\{-5,\,5\}}\\\\\\ \textsf{or in interval notation}\\\\ \mathsf{D_C=\left]-\infty,\,-5\right[\,\cup\,\left]-5,\,5\right[\,\cup\,\left]5,\,+\infty\right[\,.} \end{array}$

$\large\textsf{So pick up the one you prefer. They're equivalent ways}\\\textsf{to represent the domain.}$

If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2184171

$\large\textsf{I hope this helps. :-)}$

Tags: domain rational function fraction denominator restriction algebra

4 0

4 years ago

If -10x – 9y = -7 is a true equation, what would be the value of<br> -30x – 27y?

Tpy6a [65]

Answer:

-30x-27y = -21

Step-by-step explanation:

We know that;

-30x-27y = 3(-10x-9y)

Recall, -10x-9y = -7

Thus; -30x-27y = 3(-7) = -21

8 0

3 years ago

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steposvetlana [31]

Uhmm very interesting :)

4 0

3 years ago

Read 2 more answers

Helppp meeee plzzz thanks

melamori03 [73]

Answer:

500+4=504

Step-by-step explanation:

Hope it helps

4 0

3 years ago

Solve using the quadratic formula: 2x2-9x+12=0

marta [7]

Answer:

no solution

Step-by-step explanation:

For getting the nature of solution of the quadratic equation of the form:

ax² + bx + c = 0

We need to find Discriminant which is:

Discriminant (D) = b² - 4ac

If D < 0, there is no solution of equation.
If D = 0, there are two equal and real solution of equation
If D < 0, there are two real and distinct solution of equation

Here we have equation is:

2x² - 9x + 12 = 0

∴ a=2, b = -9, c = 12

⇒ D = 81 - 4 × 2 × 12 = -16 < 0

Hence, there is no solution of given equation.

5 0

4 years ago