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cricket20 [7]
3 years ago
6

The most important chemical regulator of respiration is question 2 options: carbon dioxide. sodium ions. potassium ions. oxygen.

nitrogen.
Chemistry
2 answers:
Alenkinab [10]3 years ago
8 0
CARBON DIOXIDE is the most important chemical regulator of respiration. Respiration primarily is the process of gas (carbon dioxide and oxygen) exchange between the air and the person's blood. There is a signal to increase ventilation when: there is to much carbon dioxide in the blood and if there is a decrease in the pH levels of the blood.

Another important chemical regulator is oxygen. There is a signal to increase ventilation when there is a drop of oxygen levels in the body.
anzhelika [568]3 years ago
4 0
The most important chemical regulator of respiration is carbon dioxide. 
Breath control is accomplished chemically, mainly using Carbon dioxide and oxygen chemoreceptors. The most important chemical regulator of respiration is either carbon dioxide or oxygen, since the chemical regulation of breathing is different in healthy and sick individuals. 
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Water has a higher boiling point than expected because what?
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Which statement best compares the energy involved in melting with the energy involved in boiling for a given liquid?
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Calculate the mass of iron(III) oxide that contains a million iron atoms. Be sure your answer has a unit symbol if necessary, an
KiRa [710]

<u>Answer:</u> The mass of iron (II) oxide that contains a million iron atoms is 2.6\times 10^{-17}g

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We are given:

Number of iron atoms = A million = 1.0\times 10^6

The chemical formula of the given compound is Fe_2O_3

It is formed by the combination of 2 iron atoms and 3 oxygen atoms.

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of particles

1 mole of iron (II) oxide will contain = (2\times 6.022\times 10^{23})=1.2044\times 10^{24} number of iron atoms

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Molar mass of iron (II) oxide = 159.7 g/mol

Applying unitary method:

For 1.2044\times 10^{24} number of iron atoms, the mass of iron (II) oxide is 159.7 g

So, for 1.0\times 10^6 number of iron atoms, the mass of iron (II) oxide will be \frac{159.7}{1.2044\times 10^{24}}\times 1.0\times 10^6=2.6\times 10^{-17}g

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8 0
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