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KIM [24]
3 years ago
10

ENTER THE COEFFICIENTS DIRECTLY FROM THE BALANCED CHEMICAL EQUATION. do not reduce to lowest terms. for example: if 3 moles H2 r

eact with 3 moles O2, enter "3" for each, not "1".
according to the following reaction:

Ca(OH)2(aq) + 2HCl(aq) -> CaCl2(aq) + 2H20(l)

what would you multiply "moles of calcium hydroxide" by to convert the units of "moles of water"?

moles Ca(OH)2. (number)(unit) ÷ (number) (unit) = moles H2O
Chemistry
1 answer:
dlinn [17]3 years ago
4 0

Answer:

The coefficients are 2 for H₂O and 1 for Ca(OH)₂.

Explanation:

Let's consider the following reaction.

Ca(OH)₂(aq) + 2 HCl(aq) → CaCl₂(aq) + 2 H₂O(l)

According to the balanced equation, the molar ratio of H₂O to Ca(OH)₂ is 2:1. Using this conversion factor, we have the following proportion:

moles Ca(OH)₂. (2 mol H₂O ÷ 1 mol Ca(OH)₂) = moles H₂O

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425,000 mL = __ L in metric conversion
saveliy_v [14]

Answer:

425l

Explanation:

m = 10^-³

425000ml

425000 x 10^-³l

425l

7 0
3 years ago
A compound is found to contain 26.73 % phosphorus, 12.09 % nitrogen, and 61.18 % chlorine by mass. What is the empirical formula
Mrrafil [7]

Answer:

PNCl_2

Explanation:

Hello!

In this case, when determining empirical formulas by knowing the by-mass percent, we first must assume the percentages as masses so we can compute the moles of each element:

n_P=\frac{26.73g}{30.97g/mol}=0.863mol\\\\n_N=\frac{12.09g}{14.01g/mol}=0.863mol\\\\n_C_l=\frac{61.18g}{35.45g/mol}=1.726mol

Now, for the determination of the subscript of each element in the empirical formula, we divide the moles by the fewest moles (P or N):

P=\frac{0.863mol}{0.863mol}=1\\\\N= \frac{0.863mol}{0.863mol}=1\\\\Cl=\frac{1.726mol}{0.863mol}2

Thus, the empirical formula is:

PNCl_2

Regards!

4 0
3 years ago
You are trying to determine the volume of the balloon needed to match the density of the air in the lab. You know that if you ca
asambeis [7]
Answer is: <span>volume of balloon is </span>476,85 cm³.
density of air: d(air) = -0,0043 · 18,0°C + 1,2874.
d(air) = 1,21 kg/m³ = 1,21 · 10³/ 10⁶ = 0,00121 g/cm³.
m(balloon) = 0,577 g.
d(balloon) = d(air).
d(balloon) = m(balloon) ÷ V(balloon).
V(balloon) = m(balloon) ÷ d(balloon)
V(balloon) = 0,577 g ÷ 0,00121 g/cm³.
V(balloon) = 476,85 cm³.
8 0
3 years ago
What are the two measurement systems the thermometer uses? Which one is most commonly used for science? Why?
bija089 [108]
The two are Celsius and Kelvin. the most used is Kelvin. the reason is that it is more precise measurement.  
4 0
3 years ago
which of the following will stay consant, no matter if the substance is in the solid, liquid, or gas state​
777dan777 [17]

Answer:

chemical composition

Explanation:

changes into any state of matter are physical and thus the chemical composition of the matter is unaltered

8 0
3 years ago
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