How complex fractions can be used to solve problems with ratios
1 answer:
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See the picture to better understand the problem
we know that
in the triangle ABC
∠A+∠B+∠C=180°
find ∠C
∠C=180-[80+65]------> ∠C=35°
Applying the law of sines
AB/sin C=CB/sin A
solve for CB
CB=AB*sin A/sin C-----> CB=45*sin 65/sin 35-----> CB=71.10 ft
the answer is
<span>the distance from person B to the top of the hill is 71.10 feet</span>
we know that
in the triangle ABC
∠A+∠B+∠C=180°
find ∠C
∠C=180-[80+65]------> ∠C=35°
Applying the law of sines
AB/sin C=CB/sin A
solve for CB
CB=AB*sin A/sin C-----> CB=45*sin 65/sin 35-----> CB=71.10 ft
the answer is
<span>the distance from person B to the top of the hill is 71.10 feet</span>