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2 years ago

How complex fractions can be used to solve problems with ratios

1 answer:

4 0

When you have ratios and some unknowns,you can create complex fractions from them.Bring them to the same denominator and solve for X.

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A circular table top has a radius of 60cm. A force of 650N is applied to the whole table top. Calculate the pressure in N/m to 4

ikadub [295]

Answer:

i hope its understood....

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2 years ago

Four classmates collect data by conducting a poll. They

Stolb23 [73]

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The larger the sample size (number of people asked), the more accurate the results generally are, due to the law of large numbers.

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2 years ago

F(t) = -2t + 5 f() = 13

fomenos

Answer:

I don't know what the question is but...

Step-by-step explanation:

-2t+5-13= -2t-8

-2t+5+13=-2t+18

-2t+5*13= -2t+65

-2t+5/13= -26t-5/13

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3 years ago

Read 2 more answers

This is a quiz on special right triangles. please help me i cannot fail this. i will mark brainliest

kobusy [5.1K]

Answer:

x=4

Step-by-step explanation:

Consider ΔKLJ:

sinθ=opposite/hypotenuse

sin30=LJ/8√2

LJ=0.5*8√2=4√2

Consider ΔMLJ:

sinθ=opp/hyp

sin45=x/4√2

1/√2=x/4√2

4√2/√2=x

x=4

4 0

3 years ago

The five circles making up this archery target have diameters of length $2,4,6,8,$ and $10$. What is the total red area?

Sliva [168]

Answer:

$A=15\pi\ units^2$

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

It is given that the diameter of 5 circles making up the archery is 2,4,6,8, and 10.

To determine the total red area, we use the formula for area of the circle

$A=\pi r^{2}$

step 1

Find the Area of the 1st red circle

$r=2/2=1\ unit$ ---> the radius is half the diameter

$A_1=\pi (1)^{2}=\pi\ units^2$

step 2

Find the Area of the 2nd white circle

$r=4/2=2\ units$ ---> the radius is half the diameter

$A_2=\pi (2)^{2}=4\pi\ units^2$

step 3

Find the Area of the 3rd red circle

$r=6/2=3\ units$ ---> the radius is half the diameter

$A_3=\pi (3)^{2}=9\pi\ units^2$

step 4

Find the Area of the 4th white circle

$r=8/2=4\ units$ ---> the radius is half the diameter

$A_4=\pi (4)^{2}=16\pi\ units^2$

step 5

Find the Area of the 5th red circle

$r=10/2=5\ units$ ---> the radius is half the diameter

$A_5=\pi (5)^{2}=25\pi\ units^2$

The total red area is given by

$A=A_5-A_4+A_3-A_2+A_1$

substitute

$A=25\pi-16\pi+9\pi-4\pi+\pi$

$A=15\pi\ units^2$

7 0

2 years ago