How complex fractions can be used to solve problems with ratios

$\begin{array}{ccc}{Industry} & {Frequency} & {\%Frequency} & {Bank} & {26} & {13\%} & {Cable} & {44} & {22\%} & {Car} & {42} & {21\%}& {Cell} & {60} & {30\%} & {Collection} & {28} & {14\%} & {Total} & {200} & {100\%} \ \end{array}$

(b): Cell industry

(c) See Explanation

Step-by-step explanation:

Given (Missing from the question)

$Bank = 26$

$Cable = 44$

$Car = 42$

$Cell = 60$

$Collection = 28$

$Total = 200$

Solving (a) Show the frequency and percent frequency.

The percentage frequency is calculated by:

$\%Freq = \frac{Freq}{Total} * 100\%$

So. we have:

$\%Freq = \frac{26}{200} * 100\% = 13\%$ -- Bank

$\%Freq = \frac{44}{200} * 100\% = 22\%$ --- Cable

$\%Freq = \frac{42}{200} * 100\% = 21\%$ --- Car

$\%Freq = \frac{60}{200} * 100\% = 30\%$ --- Cell

$\%Freq = \frac{28}{200} * 100\% = 14\%$ --- Collection

The table becomes:

$\begin{array}{ccc}{Industry} & {Frequency} & {\%Frequency} & {Bank} & {26} & {13\%} & {Cable} & {44} & {22\%} & {Car} & {42} & {21\%}& {Cell} & {60} & {30\%} & {Collection} & {28} & {14\%} & {Total} & {200} & {100\%} \ \end{array}$

Solving (b): The industry with the highest complaints

From the above table, the highest frequency is 60 and this represents the number of complaints of Cell industry.

Hence, the cell industry has the highest number of complaints

Solving (c): Comment

The percentage frequency table shows that the industry with the highest number of complaints is the cell industry (at 30%) and the industry with the least is the banking industry (at 13%)

5 0

3 years ago

1/3÷100 will the answer be smaller than 1 close to 1 or much greater than 1

Radda [10]

Answer:

It will be smaller than one

Step-by-step explanation:

because i said so

7 0

3 years ago