Help PLEASE!!! Find X for the triangle.

Mathematics

1 answer:

aleksklad [387]3 years ago

8 0

Answer:

Step-by-step explanation:

$Hypotenuse = 8\sqrt{2} \\Adjacent =x\\\alpha =45\\\\Using\: SOHCAHTOA\\Cos \alpha = \frac{Adjacent}{Hypotenuse}\\\\Cos 45 = \frac{x}{8\sqrt{2} } \\\frac{\sqrt{2} }{2} =\frac{x}{8\sqrt{2} }\\ \\Cross \: Multiply\\2x =16\\\frac{2x}{2} =\frac{16}{2} \\\\x =8$

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<em>Additional comment</em>

The order of operations tells you to simplify inside parentheses first. Doing that reduces the work somewhat.

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