Consider the following.f(x)=74 – x2Find the x-values at which f is not continuous. Which of the discontinuities are removable?
1 answer:
Answer
given,
f(x) = 74 - x²
A function is continuous when it is differential at all the points.
so, the given function is continuous for all the value of x.
We should know that if a function is quadratic then it is differential at all the point. And if it is differential then it is definitely continuous.
Hence, there is no discontinuous point present in the equation.
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Hey there :)
We know the distance formula is:
D =
1) Coordinates are: ( -10, -5 ) , ( 8 , 5 )
↓ ↓ ↓ ↓
x₁ y₁ x₂ y₂
We plug in the values
D =
≈20.59 ≈ 20.6 (nearest tenth)
We do the same for the rest
2) Coordinates are ( 10 , 0 ) , ( -2 , 1 )
D =
≈ 12.04 ≈ 12.0 (nearest tenth)
3) Coordinates are ( 4 , 8 ) , ( 7 , -8 )
D =
≈ 16.27 ≈ 16.3 (nearest tenth)
4) Coordinates are ( -10, -4 ) , ( 8 , 8 )
D =
≈ 21.6 (nearest tenth)
5) Coordinates are ( 6 , -3 ) , ( -8 , 9 )
D =
≈ 18.4 (nearest tenth)
You can find the matching below :)
We know the distance formula is:
D =
1) Coordinates are: ( -10, -5 ) , ( 8 , 5 )
↓ ↓ ↓ ↓
x₁ y₁ x₂ y₂
We plug in the values
D =
≈20.59 ≈ 20.6 (nearest tenth)
We do the same for the rest
2) Coordinates are ( 10 , 0 ) , ( -2 , 1 )
D =
≈ 12.04 ≈ 12.0 (nearest tenth)
3) Coordinates are ( 4 , 8 ) , ( 7 , -8 )
D =
≈ 16.27 ≈ 16.3 (nearest tenth)
4) Coordinates are ( -10, -4 ) , ( 8 , 8 )
D =
≈ 21.6 (nearest tenth)
5) Coordinates are ( 6 , -3 ) , ( -8 , 9 )
D =
≈ 18.4 (nearest tenth)
You can find the matching below :)