Question

What is the standard form of the points (-3,4) (2,-6)

Answer 1

The standard form equation of the line connecting the two points is $2x + y = -2$

Linear equation in a standard form is given as $Ax + By = C$

where,

A, B, and C are constants or numbers

x and y are the variables.

To solve this problem, the following steps would be taken:

Step 1: Find the slope of the line connecting points (-3,4) and (2,-6)

$slope (m) = \frac{y_2 - y_1}{x_2 - x_1}$

where,

$(x_1, y_1) = (-3,4)\\(x_2, y_2) = (2,-6)$

Substitute

$slope (m) = \frac{-6 - 4}{2 -(-3)} \\m = \frac{-10}{5}\\m = -2$

Step 2: Find the y-intercept (b) of the line by substituting $(x, y) = (-3,4)$ and $m = -2$ into $y = mx + b$ (slope-intercept form)

$4 = -2(-3) + b\\4 = 6 + b\\4 - 6 = 6 + b - 6\\-2 = b\\b = -2$

Step 3: Write the equation of the line in slope-intercept form by substituting $m = -2$ and $b = -2$ into $y = mx + b$

$y = -2x + (-2)\\y = -2x - 2$

Step 4: Rewrite the equation in standard form $(Ax + By = C)$

$y = -2x - 2$

Add $2x$ to both sides

$2x + y = -2x - 2 + 2x\\2x + y = -2$

The standard form equation of the points (-3,4) and (2,-6) is $2x + y = -2$

Learn more about standard form of two points of a linear equation here:

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