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3 years ago

How many solutions does the system 2y=10x-14 and 5x-y=7 have? need worked out step by step please!

Mathematics

2 answers:

solniwko [45]3 years ago

5 0

These 2 equations are actually the same,
hope u can understand.

VLD [36.1K]3 years ago

3 0

2y=10x-14
5x-y=7

Divide both sides by 2 in the 1st equation
y=5x-7
Now substitute is to 2nd equation
5x-5x+7=7
0=0

Therefore there is no solution or it is inconsistent

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Answer:

$x=-1$

Step-by-step explanation:

$\frac{7}{2}x+\frac{1}{2}x=\frac{1}{2}+\frac{9}{2}x$

Step 1: Simplify both sides of the equation.

$\frac{7}{2}x+\frac{1}{2}x=\frac{1}{2}+\frac{9}{2}x$

$(\frac{7}{2}x+\frac{1}{2}x)=\frac{9}{2}x+\frac{1}{2}$ (Combine Like Terms)

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Step 2: Subtract $\frac{9}{2}x$ from both sides.

$4x-\frac{9}{2}x=\frac{9}{2}x+\frac{1}{2}-\frac{9}{2}x$

$\frac{-1}{2}x=\frac{1}{2}$

Step 3: Multiply both sides by $(\frac{2}{-1})$ .

$(\frac{2}{-1})*(\frac{-1}{2}x)=(\frac{2}{-1})*(\frac{1}{2})$

$x=-1$

Therefore, $x=-1$ will be your final answer.

Sorry this took very long. I had to calculate all of this.

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