Solve by substitution: <br> Y= 2x+5 <br> Y=2x+1

If the exterior angle of a regular polygon is 7.2 degrees, what is the name of that polygon?

kirill [66]

A regular polygon with exterior angle of 7.2 degrees is a 50-gon.

<h3>Regular polygon</h3>

Regular polygon are polygon that are equiangular. This simply means they are polygon with equal angles.

The formula to find the number of sides of a polygon using exterior angle is as follows:

exterior angle = 360 / n

where

n = number of sides

Therefore,

7.2 = 360 / n

cross multiply

7.2n = 360

divide both sides by 7.2

n = 360 / 7.2

n = 50

The polygon has 50 sides. Therefore, it is a 50-gon

learn more on polygon here: brainly.com/question/12105506

8 0

2 years ago

Write 37/100 as a percentage.

insens350 [35]

Answer:

37%

Step-by-step explanation:

37% equal 37 of a whole 100 is a whole

7 0

3 years ago

Read 2 more answers

Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel

nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

$\theta=\frac{\pi}{3}$

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be= $r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j$

By using $cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}$

Force along the plane will be= $\mid F_x\mid=F\cdot r$

Force along the plane will be = $\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3$ N

By using $i\cdot i=j\cdoty j=k\cdot k=1,i\cdot j=j\cdot k=k\cdot i=j\cdot i=k\cdot j=i\cdot k=0$

Therefore, force along the plane= $\mid F_x\mid(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)$

2.The vector perpendicular to the plane= $r=-sin\frac{\pi}{3}-cos\frac{\pi}{3}=-\frac{\sqrt 3}{2}i-\frac{1}{2}j$

The force perpendicular to the plane= $\mid F_y\mid=F\cdot r=-8j(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

The force perpendicular to the plane= $4$ N

Therefore, $F_y=4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

Sum of two component of force= $F_x+F_y=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)+4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)$

Sum of two component of force= $2\sqrt 3i-6j-2\sqrt3 i-2j=-8j$

Hence,sum of two component of forces=Total force.

6 0

2 years ago

Suppose you invest $500 at an annual interest rate of 8.2% compounded continuously. How much will you have in the account after

Marianna [84]

Here is the formula that your going to need to use A=P(1+r/n)^nt
So P=500, R=0.082, N=1, T=15
Plug it into your equation and you have A=500(1+0.082/1)^(1)(15)
Simplify what's in the parenthesis A=500(1.082)^(1)(15)
Multiply your exponents A=500(1.082)^15 Then A=500(3.26)
Finally you multiply your last two numbers to get A=1,630
So after 15 years you would have $1,630
I hope this helped you :)

7 0

3 years ago

Which has the same value as 1 5 tens?

Olenka [21]

The answer would be 150 as each ten bar is si worth 10 and 10x15=150.

8 0

3 years ago

Solve by substitution: Y= 2x+5 Y=2x+1