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3 years ago

Number 5 i don’t know what to plug in for the original height

Mathematics

1 answer:

rewona [7]3 years ago

4 0

Answer:

original height = .2(8) + 13.4 = 15 inches

Step-by-step explanation:

To find the original height you multiply .2 by 8 to see how much was burned and then you add that to whats left (13.4) to give you the original height.

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Help me find the rate of change for these points listed here, and also write an equation:

valentinak56 [21]

54-2/0-3=-17,3=a
Y=-17,3x+54 b=54 because its the initial value of y when x =0
When x=1 y=36,7
When x=2 y=19,4
I juste replaced 1 in the equation and did the calculation with my calculator

4 0

3 years ago

2. When Joey dives off a diving board, the equation of his pathway can be modeled by h = -16- + 15 + 12.

Sergeu [11.5K]

Answer:

a) The maximum height is approx 15.5 unit.

b) The time it will take for Joey to reach the water is 1.45 hour.

Step-by-step explanation:

Given : When Joey dives off a diving board, the equation of his pathway can be modeled by $h(t)= -16t^2+15t + 12$

To find : a) Find Joey's maximum height.

b) Find the time it will take for Joey to reach the water.

Solution :

Modeled $h(t)= -16t^2+15t + 12$ ....(1)

a) To find maximum height

Derivate (1) w.r.t. t,

$h'= -32t+15$

For critical point put h'=0,

$-32t+15=0$

$t=\frac{15}{32}$

$t=0.46875$

Derivate again w.r.t. t,

$h''= -32$

It is maximum at t=0.46875.

Substitute t in equation (1),

$h(0.46875)= -16(0.46875)^2+15(0.46875)+12$

$h(0.46875)= -3.515625+7.03125+12$

$h(0.46875)= 15.515625$

The maximum height is approx 15.5 unit.

b) To find the time it will take for Joey to reach the water.

Put h=0 in equation (1),

$-16t^2+15t + 12=0$

Apply quadratic formula, $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Here, a=-16 , b=15, c=12

$t=\frac{-15\pm\sqrt{(15)^2-4(-16)(12)}}{2(-16)}$

$t=\frac{-15\pm\sqrt{225+768}}{-32}$

$t=\frac{-15\pm\sqrt{993}}{-32}$

$t=\frac{-15+\sqrt{993}}{-32},\frac{-15-\sqrt{993}}{-32}$

$t=−0.515,1.453$

Reject negative value.

The time is t=1.45.

The time it will take for Joey to reach the water is 1.45 hour.

5 0

3 years ago

Brenda has two remote-controlled race cars painted blue and red, respectively.The blue car traveled 54 feet 4 secounds.The red c

Angelina_Jolie [31]

Answer:

The red car is faster compared to the blue car.

The red car is faster by 5.5 feet than the blue car.

Step-by-step explanation:

The objective is to find which car is faster and by how much

Given that:

The blue car traveled 54 feet in 4 seconds; &

The red car traveled 38 feet in 2 seconds.

Let us determine the number of feet traveled in each second for both cases.

For the blue car:

In 1 second, the car will travel = 54/4 feet

In 1 second, the car will travel = 13.5 feet

For the red car:

In 1 second, the car will travel = 38/2 feet

In 1 second, the car will travel = 19 feet

Thus, the red car is faster compared to the blue car.

The distance at which the red car is faster than the blue car = 19 feet - 13.5 feet

= 5.5 feet

4 0

3 years ago

Simplify the expression using the order of operations: (21−3)÷32 6th grade math btw

amid [387]

Answer:

9/16

Step-by-step explanation:

3 0

3 years ago

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son4ous [18]

Answer:

the measurement of YVX is 88°

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3 years ago