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3 years ago

Hi uwu pls help me?? i really need it :'( dont make me cry

Mathematics

1 answer:

densk [106]3 years ago

8 0

Answer:

4z-(3z) z

Step-by-step explanation:

I hope that helps

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Please help!!! it’s due today!! 37 POINTS

notsponge [240]

i think it's 118 i don't know because I studied this 4 years ago

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3 years ago

Darron use a family recipe to make hamburgers. If he plans on using 1 1/3 cups of bread crumbs, about how many pounds of hamburg

Tpy6a [65]

What are the choices, or do you have to give the answer?

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3 years ago

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I need help asap !!!!!!!!

Marrrta [24]

Answer:

Page 1: 2u - 3v = < -7, 1 >

Page 2: < -7, 9 >

Step-by-step explanation:

Page 1: Given u and v, we need 2u - 3v. With vectors, you can multiply both terms by any scalar (the coefficient, i.e. 2u, the 2 is the scalar)

2u = 2<1, 2> = <2, 4>

3v = 3<3, 1> = <9, 3>

So 2u - 3v = <2, 4> - <9, 3> = <2 - 9, 4 - 3> = <-7, 1>

Page 2: The same steps apply, but when you see i and j, the coefficient of the i term is the x value, and the coefficient of the j term is the y value, so

3u - 2v = 3< 1, 1> - 2<5, -3> = <3, 3> - <10, -6> = <3 - 10, 3 - (-6)> = <-7, 9>

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4 years ago

Read 2 more answers

How to rewrite√-49 -4 in complex number notation

stira [4]

Sqrt(49)*sqrt (-1) -4 = 7i-4

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3 years ago

According to a study conducted by an organization, the proportion of Americans who were afraid to fly in 2006 was 0.10. A rando

Nimfa-mama [501]

Answer: No, this is not necessarily evidence that the proportion of Americans who are afraid to fly has increased.

Step-by-step explanation:

Since we have given that

n = 1400

x = 154

So, $\hat{p}=\dfrac{154}{1400}=0.11$

and p = 0.10

So, hypothesis would be

$H_0:\hat{p}=p\\\\H_a:\hat{p}>p$

So, the test statistic value would be

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\z=\dfrac{0.11-0.10}{\sqrt{\dfrac{0.1\times 0.9}{1400}}}\\\\z=\dfrac{0.01}{0.008}\\\\z=1.25$

At 5% level of significance,

critical value would be 1.96.

Since 1.96>1.25.

so, we will accept the null hypothesis.

Hence, no, this is not necessarily evidence that the proportion of Americans who are afraid to fly has increased.

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3 years ago