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olga_2 [115]
3 years ago
9

400 TIMES 45.2 USING PARTIAL PRODUCTS

Mathematics
2 answers:
Irina-Kira [14]3 years ago
5 0
The answer is 18,080
Romashka-Z-Leto [24]3 years ago
5 0
I think it's 18,080. ..........
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Help me with this... ​
marin [14]

i. 171

ii. 162

iii. 297

Solution,

n(U)= 630

n(I)= 333

n(T)= 168

i. Let n(I intersection T ) be X

333 - x + x + 468 - x = 630 \\ or \: 333 + 468 - x = 630 \\ or \: 801 - x = 630 \\ or \:  - x = 630 - 801 \\ or \:  - x =  - 171 \\ x = 171

<h3>ii.n(only I)= n(I) - n(I intersection T)</h3><h3> = 333 - 171</h3><h3> = 162</h3>

<h3>iii. n ( only T)= n( T) - n( I intersection T)</h3><h3> = 468 - 171</h3><h3> = 297</h3>

<h3>Venn- diagram is shown in the attached picture.</h3>

Hope this helps...

Good luck on your assignment...

4 0
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Folders are on sale for $0.15 each. Notebooks are $4.25 each. There are 225 students in 7th grade. What is the total amount it w
Harrizon [31]

Answer:

$1023.75

Step-by-step explanation:

2*.15=.30 + 4.25= 4.55

4.55 * 225 = 1023.75

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