Answer:
A=14cm²
Step-by-step explanation:
A=hbb
2=7·4
2=14cm²
Ok so
Q.1=B
Q.2=B
Q.3(a)=(d-45)+m+65
(b)=d+m+20
Answer:
see explanation
Step-by-step explanation:
(a)
Given
2k - 6k² + 4k³ ← factor out 2k from each term
= 2k(1 - 3k + 2k²)
To factor the quadratic
Consider the factors of the product of the constant term ( 1) and the coefficient of the k² term (+ 2) which sum to give the coefficient of the k- term (- 3)
The factors are - 1 and - 2
Use these factors to split the k- term
1 - k - 2k + 2k² ( factor the first/second and third/fourth terms )
1(1 - k) - 2k(1 - k) ← factor out (1 - k) from each term
= (1 - k)(1 - 2k)
1 - 3k + 2k² = (1 - k)(1 - 2k) and
2k - 6k² + 4k³ = 2k(1 - k)(1 - 2k)
(b)
Given
2ax - 4ay + 3bx - 6by ( factor the first/second and third/fourth terms )
= 2a(x - 2y) + 3b(x - 2y) ← factor out (x - 2y) from each term
= (x - 2y)(2a + 3b)
Answer:
1. 208 in^2
Step-by-step explanation:
1. We can break the shape up into a rectangle in the middle and 2 triangles on either side of said rectangle.
The dimensions of the rectangle are 8 in by 20 in, and we only know one leg of the triangle as well as the hypotenuse.
If we know one leg and the hypotenuse we can use the pythagorean theormed to sovle for the other side and get 6 in.
So we have
(8 * 20) + 2((1/2)(6)(8))
160 + 48
208 in^2
