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Schach [20]
3 years ago
10

What is its average acceleration in this time interval?

Physics
1 answer:
hodyreva [135]3 years ago
5 0

Answer:

Unlike acceleration, the average acceleration is calculated for a given interval. Here, Δ v is the change in velocity and Δ t is the total time over which the velocity is changing. If the velocity of a marble increases from 0 to 60 cm/s in 3 seconds, its average acceleration would be 20 .

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two objects each weighing 2kg are lifted through the same distance in 4s and 1s respectively. which scenario requires more work?
Shalnov [3]

i believe it would be the same because time doesn't matter when calculating total work done.

Work=FxD

F=force

D=distance


7 0
3 years ago
Why do people cry but dont say whats wrong they jus stand and act like we kno wha wrong
Finger [1]

Answer:

usually its because they dont wanna talk

Explanation:

I know what thats  like. Either that or they don't trust you. It could be something personal or they just dont wanna talk. But i wouldn't push. Just let them talk if they want to

5 0
4 years ago
An alpha particle travels at a velocity of magnitude 520 m/s through a uniform magnetic field of magnitude 0.034 T. (An alpha pa
Keith_Richards [23]

Answer:

(a) Magnetic force F=38.584\times 10^{-19}N

(b) Acceleration a=5.846\times 10^8m/sec^2

(C) Speed will remain same

Explanation:

We have given velocity of alpha particle v = 520 m/sec

Magnetic field B = 0.034 T

Charge on alpha particle q=3.2\times 10^{-19}C

Mass of alpha particle m=6.6\times 10^{-27}kg

Angle between velocity and magnetic field 43°

(a) Force acting on the particle is equal to

F=q(v\times B)=qvBsin\Theta

F=3.2\times 10^{-19}\times 320\times 0.034\times sin43^{\circ}

F=38.584\times 10^{-19}N

(B) According to newton's law

F = ma. here m is mass and a is acceleration.

So acceleration

a=\frac{F}{m}=\frac{38.584\times 10^{-19}}{6.6\times 10^{-27}}=5.846\times 10^8m/sec^2

(c) As the magnetic force is always perpendicular to velocity so speed will remain same neither decreases nor increases.

4 0
3 years ago
An 3-kg object is dropped from a height of 5 m. The rock has an impact speed<br><br> of
Andrews [41]

Answer:

The rock has an impact speed  of 9.9 m/s.

Explanation:

given information:

object's mass, m = 3 kg

height, h = 5 m

in this case, the potential energy is equal to the kinetic energy

PE = KE

mgh = \frac{1}{2} mv²

where

m = mass (kg)

g = gravitational constant (9.8 m/s²)

v = velocity (m/s)

so,

mgh = \frac{1}{2} mv²

gh = \frac{1}{2} v²

v² = 2gh

v = √2gh

  = √(2)(9.8)(5)

  = 9.9 m/s

6 0
4 years ago
Sitting at the top of a steep hill on a roller coaster (not moving), is an example of:
Marianna [84]
It’s an example of gravitational potential energy
3 0
3 years ago
Read 2 more answers
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